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photoshop1234 [79]
3 years ago
7

HELP! WILL MARK BRAINLIEST

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:

it is b

Step-by-step explanation:

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Consider functions f and g below.
Scrat [10]
Answer: -12 x^2 - 3x + 27  

In this question, there are two function of f(x) and g(x) 
f(x)= -9 x^2 - 7x + 12
g(x)= 3x^2 -4x -15
The question is about f(x)- g(x). To answer this, you just need to replace the question with the function. Don't forget to apply the minus to all the product inside the function. The calculation would be:

f(x)- g(x)= 
(-9 x^2 - 7x + 12) -(3x^2 -4x -15)=
-9 x^2 - 7x + 12 (-3x^2 +4x +15)= 
-12 x^2 - 3x + 27  
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Why do we use a coeficient to remove the propotionality
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Number 9 I need help
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650 multiplied by 5 because 100÷20 =5
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Jessica is shopping for a new car. She found a blue car that has a 12-gallon gas tank and can go 384 miles on one tank. She foun
adelina 88 [10]

Answer:

Silver car

Step-by-step explanation:

It seems pretty hard but it's actually REALLY easy. gas mileage means the number of miles you can go on a particular amount of gallons. But the gallons have to be the same for both cars so that it's fair.

so let's go with 10 gallons. pretty broad number right?

so to get 12 gallons(the gallons for the blue car) to 10, We divide it by 12 then multiply it by 10. Try it yourself, (12/12)*10=???

then we do that to 384 (the miles for the blue car)

(384/12)*10=320

so 320 is the mileage for the first car. Repeat the steps for the silver car!

(14/14)*10=10

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So which is bigger, 320 or 360?

360 is bigger, meaning it has better gas mileage.

5 0
2 years ago
QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
3 years ago
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