Question

Francesca leaves her home and Drive South 150 km. Then she drives West 70 km. At this point, she drives North 30 km. Finally, she drives east 20 km. How far is she from her home? Included diagram of her trip.

Answer 1

To find the distance between her home and her latest position:

According to the question, the diagram is,

Consider the right triangle,

AB=120 km

BC=50 km

To find AC:

Using Pythagoras theorem,

$\begin{gathered} AC^2=AB^2+BC^2_{} \\ =120^2+50^2 \\ =14400+2500 \\ =16900 \\ =130\text{ km} \end{gathered}$

Hence, the distance between the new position and her home is 130 km.