All categories

2 years ago

Hehehehehehehhehehehehsdhhd

Mathematics

1 answer:

Sveta_85 [38]2 years ago

3 0

Answer:

32 miles

Step-by-step explanation:

You might be interested in

Would I distribute or foil first -2(b-2)(b-2)

7nadin3 [17]

You would distribute the -2 and the first b-2
-2xb= -2b
-2x-2= 2
So it would now be -2b - 2 (b-2)

7 0

3 years ago

Work out, giving your answer in its simplest form:<br> 4/7 divided by 2 1 / 3

Vitek1552 [10]

Step-by-step explanation:

4/7÷21/3

=4/7*3/21

=12/147

8 0

2 years ago

Read 2 more answers

Find the center and radius of the circle with the equation:

denpristay [2]

Answer:

It’s 14

Step-by-step explanation:

Just add

6 0

2 years ago

Determine what type of model best fits the given situation:

lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = $\frac{20}{100} \times P = 0.2P$

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = $\frac{20}{100} \times 0.8P = (0.2)(0.8P)$

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

$=P(0.8)^{2}$ -------------------------(2)

Similarly after 3 years, this value $P(0.8)^{2}$ will again be decreased by 20 %

so 20% of $P(0.8)^{2} \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}$

So after 3 years value is decreased by $(0.2)P(0.8)^{2}$

so value after 3 years will be = $P(0.8)^{2} - (0.2)P(0.8)^{2}$

taking $P(0.8)^{2}$ common out we get $P(0.8)^{2}(1-0.2)$

$P(0.8)^{2}(0.8)$

$P(0.8)^{3}$ -----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or $P(0.8)^{1}$

value after 2 years is $P(0.8)^{2}$

value after 3 years is $P(0.8)^{3}$

so value after x years will be $P(0.8)^{x}$ ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

$y = P(0.8)^{x}$ where y is the value after x years

so thats the final answer

3 0

3 years ago

Find each sum simplify if possible

notsponge [240]

That's simplied already, unless they want a decimal then it's .6 or something

7 0

3 years ago