Answer:
1
Step-by-step explanation:
You "complete the square" by adding the square of half the x-term coefficient. Here, that is ...
((-2)/2)² = 1 . . . . value added to complete the square
If you want to keep 0 on the right, you must also subtract this value:
x² -2x -36 = 0
x² -2x +1 -36 -1 = 0 . . . . . . add and subtract 1 on the left
(x -1)² -37 = 0 . . . . . . . . . . . written as a square
Answer:
The area of the rectangle is 1222 units²
Step-by-step explanation:
The formula of the perimeter of a rectangle is P = 2(L + W), where L is its length and W is its width
The formula of the area of a rectangle is A = L × W
∵ The length of a rectangle is 5 less than twice the width
- Assume that the width of the rectangle is x units and multiply
x by 2 and subtract 5 from the product to find its length
∴ W = x
∴ L = 2x - 5
- Use the formula of the perimeter above to find its perimeter
∵ P = 2(2x - 5 + x)
∴ P = 2(3x - 5)
- Multiply the bracket by 2
∴ P = 6x - 10
∵ The perimeter of the rectangle is 146 units
∴ P = 146
- Equate the two expression of P
∴ 6x - 10 = 146
- Add 10 to both sides
∴ 6x = 156
- Divide both sides by 6
∴ x = 26
Substitute the value of x in W and L expressions
∴ W = 26 units
∴ L = 2(26) - 5 = 52 - 5
∴ L = 47 units
Now use the formula of the area to find the area of the rectangle
∵ A = 47 × 26
∴ A = 1222 units²
∴ The area of the rectangle is 1222 units²
Answer:
B. 81 weeks
Step-by-step explanation:
If we plug everything into the equation it should look like this:

Then we would subtract 1 from both sides, then we are left with <em>w:</em>
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<em>Hope this helps!</em>
Answer:
Area_lawn = 393.75 π ft^2
Step-by-step explanation:
Maximum radius : 30 feet
Minimum radius: 30 feet - 0.25*(30feet) = 22.5 feet
(25 percent reduction)
To find the area of lawn that can be watered, we just need to calculate the area for the maximum radius and the minimum radius, and then subtract them.
Since the sprinklers have a circular area:
Area = π*radius^2
Max area = π*(30 ft)^2 = 900π ft^2
Min area = π*(22.5 ft)^2 = 506.25π ft^2
Maximum area of lawn that can be watered by the sprinkler:
Area_lawn = Max area - Min area = 900π ft^2 -506.25π ft^2
Area_lawn = 393.75 π ft^2
The point (-3,11) is a solution to : y > = x - 2, 2x + y < = 5