The mean absolute deviation for the number of hours students practiced the violin is 6.4.
<h3>What is the mean absolute deviation?</h3>
The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.
Given
Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.
The given data set is;
45, 38, 52, 58, 42
Mean Deviation = Σ|x − μ|/N.
μ = mean, and N = total number of values
|x − μ| = |45 − 47| = 2
|38− 47| = 9
|52− 47| = 5
|58− 47| = 11
|42− 47| = 5
The mean absolute deviation for the number of hours students practiced the violin is;

Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.
To know more about mean value click the link given below.
brainly.com/question/5003198
Answer:78phy
gigh[ood9..8d55.5.5.5.5.5.5.5.6.s7s47.4
Step-by-step explanation:
Answer:
133.33
Step-by-step explanation:
Answer:
1) 4+n<13
2) 11-n>17
3) n-8≥9 or n+(-8)≥9
4) 16<8n
5) n·5≤30
Step-by-step explanation:
Yes and the correct one is A