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CaHeK987 [17]
3 years ago
14

Will give brainliest please help:)Simplify: -3-8(-5x - 1)​

Mathematics
2 answers:
alex41 [277]3 years ago
7 0

Answer:

5+40x

Step-by-step explanation:

I hope this helps. Best of luck.

MariettaO [177]3 years ago
3 0

Answer:

-11 times by -6x

Step-by-step explanation:

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Solve for the answer -1/2>3/4
ikadub [295]

Answer:

no solution ...................

7 0
3 years ago
Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'
aleksandr82 [10.1K]

Answer:

A. △P'Q'R' does not equal △P''Q''R''.

B. Reflecting across UT would change the orientation of the figure.

C. The sequence does not include a reflection that exchanges U and S.

D. Rotating about point U is not a rigid motion because it changes the orientation of the figure.

E. Translating point R' to Q' is a non-invertible transformation because it changes the location of P'.

(D) Rotating about U is not a rigid motion because it changes the orientation of the figure. [I think D is an incorrect answer choice.]

Step-by-step explanation:

Proof No.1

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R' about point U to get △P''Q''R''. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

Proof No.2

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R about point U to get △P''Q''R'' so that R''Q'' and UT coincide. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

8 0
3 years ago
What is the slope of the line that passes through the points (-9,8) and (-21,10)?
____ [38]

Answer:

Step-by-step explanation:

(10 - 8)/(-21 + 9)= 12/-12= -1

y - 8 = -1(x + 9)

y - 8 = -x - 9

y = -x - 1

4 0
3 years ago
If Y / 4 - 12 = 3.5, what is the value of y?
qwelly [4]

Answer:

ok so the answer o Y is -8 bc  4-12 = -8 so really is -8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,
myrzilka [38]

Answer:

163.83-4.03\frac{20.094}{\sqrt{6}}=130.77    

163.83+4.03\frac{20.094}{\sqrt{6}}=196.89    

So on this case the 99% confidence interval would be given by (130.77;196.89)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 175 177 175 180 138 138

We can calculate the mean and the deviation from these data with the following formulas:

\bar X= \frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=163.83 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=20.093 represent the sample standard deviation

n=6 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=6-1=5

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,5)".And we see that t_{\alpha/2}=4.03

Now we have everything in order to replace into formula (1):

163.83-4.03\frac{20.094}{\sqrt{6}}=130.77    

163.83+4.03\frac{20.094}{\sqrt{6}}=196.89    

So on this case the 99% confidence interval would be given by (130.77;196.89)    

7 0
3 years ago
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