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3 years ago

Pls anyone? Ill give brainliest Pls yall fr

Mathematics

2 answers:

Lena [83]3 years ago

4 0

Answer:

Question 4. = 3rd Choice / 5h+2r+9y

Question 5. = 4th Choice / 31s+5

Step-by-step explanation:

Question 4:

Combine like terms.

h+8y+4h+y+2r

8y+y= 9y

4h + h = 5h

Finally, you have your answer.

5h+2r+9y

Question 5:

Combine like terms.

47s-16s+5

31s+5

Finally, you have your answer.

31s+5

dexar [7]3 years ago

3 0

Answer: |

4. C. |

5. D. |

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Sam bought 2 shirts. Deal A shirt was $20 and was on

Anastasy [175]

Answer:

Deal A was the better deal.

Step-by-step explanation:

20*.10= 2 dollar discount for a total of 20-2= $18 total

22*.16= 3.52 dollar discount for a total of 22-3.52 =$18.48

Even though deal B had the larger discount you will still be paying a bit more compared to deal A

7 0

3 years ago

In this question, i is a unit vector due east and j is a unit vector due north. A cyclist rides at a speed of 4 m/s on a bearing

d1i1m1o1n [39]

Answer:

a) 1.04i + 3.86j

b) magnitude = 8; bearing = 302.7°

Step-by-step explanation:

The first diagram represents the velocity vector of the cyclist.

To express this vector in the form xi + yj, we have to find the components of the vector in the horizontal (i) and vertical (j) directions.

If we consider the horizontal component of the vector to be $x$ , and the vertical component to be $y$ , then:

• horizontal component ⇒ $sin (15^{\circ}) = \frac{x}{4}$

⇒ $x = 4\space\ sin(15^{\circ})$

⇒ $x \approx \bf 1.04$

• vertical component ⇒ $cos(15^{\circ}) = \frac{y}{4}$

⇒ $y = 4 \space\ cos(15^{\circ})$

⇒ $y \approx \bf 3.86$

Now that we have the values of both the horizontal and vertical component, we can write the vector in the form of xi + yj:

vector ⇒ 1.04i + 3.86j

The second diagram shows the first vector (red), the second vector (blue), and the resultant vector v (black). The dashed lines represent the components of the respective vectors.

To add two vectors given their magnitudes and direction, we have to add their components.

In order to find the horizontal and vertical components of the given vectors, we can use a method similar to that used above, so that:

○ For the first vector (magnitude 6):

• horizontal component ⇒ $x = 6 \space\ sin (60^{\circ})$

⇒ $\bf 5.2$

• vertical component ⇒ $y = 6 \space\ cos(60^{\circ})$

⇒ $y = \bf 3$

○ For the second vector (magnitude 2):

• horizontal component ⇒ $x = 2 \space\ cos (40^{\circ})$

⇒ $\bf 1.5$

• vertical component ⇒ $y = 2 \space\ sin(40^{\circ})$

⇒ $\bf 1.3$

Now we can add the respective components together:

v = 5.2i + 3j + 1.5i + 1.3j

⇒ (5.2 + 1.5)i + (3 + 1.3)j

⇒ 6.7i + 4.3j

∴ Magnitude of v ⇒ $|v| = \sqrt{(6.7)^2 + (4.3)^2}$

⇒ $|v| \approx \bf 8$

To find the bearing of v, we have to first calculate the angle marked $\alpha$ :

$tan \alpha = \frac{4.3}{6.7}$

⇒ $\alpha = tan^{-1}(\frac{4.3}{6.7})$

⇒ $\alpha = \bf 32.7^{\circ}$

∴ Bearing = 270° + 32.7°

= 302.7°

8 0

2 years ago

Square root of 1536 with divison method

11111nata11111 [884]

Answer:

39.191835884531

this is the square root

3 0

4 years ago

Dylan is a salesperson who sells computers at an electronics store. He makes a base pay amount each day and then is paid a commi

algol13

P=2.50x+100

The slope of the function is 2.50 which represents the commission Dylan makes for each computer sale. :)

7 0

3 years ago

Quadratics practice, I need help on how to solve this

lapo4ka [179]

Answer:

Below in bold.

Step-by-step explanation:

x^2 - 2x - 3 = 0

(x - 3)(x + 1) = 0

The zeroes are -1, 3.

Change to vertex form:

= (x - 1)^2 - 1 - 3

= (x - 1)^2 - 4

So the axis of symmetry is x = 1.

The vertex is at (1, -4) and it is a minimum (because the coefficient of x^2 is positive).

Domain is (-∞, ∞)

Range is [-4, ∞).

Increasing when x < 1.

Decreasing when x > 1.

End behaviour x ---- -∞ , y --> ∞

x ----> ∞, y ---> ∞

8 0

3 years ago