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2 years ago

What is the density of an object that has a mass of 20 grams and has a length of 8cm and a width of 2cm and a height of 5cm????

Mathematics

1 answer:

Evgen [1.6K]2 years ago

7 0

Answer:

Volume is the amount of space an object occupies. To determine the volume of any rectangular object, multiply the measurements of length, width, and height.

Volume = Length × Width × Height

Calculate the volume of this rectangular object.

Length = 3 cm

Width = 3 cm

Height = 12 cm

Volume = l × w × h

Volume = 3 cm × 3 cm × 12 cm

Volume = 108 cm3

Notice that the units for volume are cubic centimeters (cm3).

So 8 ÷ 25 = 0.32 and the units would be g/ cm3 . Other units of density could be g/L or g/ml or mg/ cm3 or kg/ m3 and the list could go on and on. Any unit of mass divided by any unit of volume.

Step-by-step explanation:

hope this helpa

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How many ways can 4 candy bars be chosen from a store that sells 30 candy bars (combination)

Morgarella [4.7K]

Answer:

Using the combination formula:

Number of combination of r object chosen from the total object i.e n is given by:

$\frac{n!}{r! \cdot (n-r)!}$

As per the statement:

4 candy bars be chosen from a store that sells 30 candy bars

Number of candy bars chosen from a store that sells 30 candy bars(r)= 4

and

Total candy bars(n) = 30

then substitute in the given formula we have;

$\frac{30!}{4! \cdot (30-4)!}$

⇒ $\frac{30!}{4! \cdot (26)!}$

⇒ $\frac{30 \cdot 29 \cdot 28 \cdot 27 \cdot 26!}{1 \cdot 2 \cdot 3 \cdot 4 \cdot (26)!}$

Simplify:

⇒ $\frac{657720}{24} = 27,405$

therefore, 27,405 ways can 4 candy bars be chosen from a store that sells 30 candy bars

3 0

2 years ago

Read 2 more answers

Let F(x)=3x-1,h(x)=-x+5 find (f•h)(-2)

vovangra [49]

Answer:

Dont mind me if i am wrong!

4 0

2 years ago

zhenek [66]

Answer:

Step-by-step explanation:

length = x +x + 2 = 2x + 2

Width = 2+ x

Area of rectangle = length *width

(x +2)(2x + 2) = 110

Use FOIL method

x*2x + x*2 + 2*2x + 2*2 = 110

2x² + 2x + 4x + 4 - 110 = 0 {Combine like terms}

2x² +6x - 106 = 0

a = 2 ; b = 6 ; c = -106

b² - 4ac = 6² - 4*2*(-106)

= 36 + 848

= 884

$\sqrt{b^{2}-4ac}=\sqrt{884}= 29.73$

$x =\dfrac{-b+\sqrt{b^{2}-4ac}}{2a} \ ; \ x==\dfrac{-b-\sqrt{b^{2}-4ac}}{2a}\\\\x = \dfrac{-6+29.73}{2*2} \ ; \ x =\dfrac{-6-29.73}{2*2} \ this \ is \ ignored \ as \ it \ is \ negative\\\\x=\dfrac{23.73}{4};$