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2 years ago

8

There are 39 people on a city bus. The ratio of adults to children is 10 : 3. At the next stop, 3 adults get off the bus. What i

s the new ratio of adults to children on the bus?
A 3 : 1

B 9 : 2

C 7 : 3

D 12 : 1

1 answer:

svp [43]2 years ago

5 0

Answer:

<u>3:1</u>

Step-by-step explanation:

Looking at the numbers

39 and a ratio of 10:3 kinda scream that there are 30 adults and 9 children to me, but when 3 adults get off, that is only 36 people.

this means,

27 adults,

and

9 children

so if it doesn't look obvious enough, 9 x 3 is 27, so that means that 3: 1 must be our ratio because the 3 in 3:1 multiplied by 9 is 27 which is the number of adults, and the 1 in children multiplied by 9 is 9!

so there you have it, 27/9 = 3

and

9/9=1

so

<u>3: 1</u>

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Tyler wants to buy a new tub and that cost $312. He has already saved the plan to save $24 per week over the next few weeks whic

laila [671]

Answer:

13 weeks

Step-by-step explanation:

Given that :

Cost of new tub = $312

Planned saving per week = $24

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5 0

3 years ago

user100 [1]

Step-by-step explanation:

f(3)=?

f(x)=2x+5

put x=3,

f(3)=2(3)+5=6+5=11

------------

g(2)=?

g(x)=x^2-3

put x=2,

g(2)=2^2-3=4-3=1

-----------------

g(f(-1))=?

g(x)=x^2-3

and f(-1)=2(-1)+5= -2+5=3

so g(f(-1))=3^2-3=9-3=6

----------------

f(g(-1))=?

f(x)=2x+5

g(x)=g(-1)=(-1)^2-3=1-3= -2

f(g(-1))=2(-2)+5= -4+5=1

----------------

g(f(x))=?

g(x)= x^2-3

put x=f(x),

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4 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

as

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

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so equation becomes

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$\frac{-4a}{-4}=\frac{8}{-4}$

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$\mathrm{Verify\:Solutions}$

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So the following points are undefined

$a=-2,\:a=2$

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3 years ago

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6 0

3 years ago