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mr Goodwill [35]
3 years ago
10

Clinton hosted an end-of-year party. He expected 5 guests, but 8 times as many showed up. How many people attended?

Mathematics
1 answer:
adell [148]3 years ago
5 0

Answer:

41 people

Step-by-step explanation:

Clinton hosted an end-of-year party. He expected 5 guests, but 8 times as many showed up. How many people attended?

The amount of guest that showed up can be calculated as:

5 guest × 8 times the number of guests

= 40 guests

The number rod people that attended the end of the year party = 40 guest + Clinton

= 41 people

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Solve the following systems of 3-variable linear equations.​<br><br><br><br>50 points
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Answer:

x = 9/25

y = 7/25

z = 4/25

Step-by-step explanation:

2x + y = 1 .......(1)

3y + z = 1 ........(2)

x + 4z = 1 ........(3)

Elimination 1 and 2

2x + y = 1 | ×3 |

3y + z = 1 | ×1 |

6x + 3y = 3

3y + z = 1

___________--

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Elimination 3 and 4

x + 4z = 1 | ×6 |

6x - z = 2 | ×1 |

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x + 4z = 1 | ×1 |

6x - z = 2 | ×4 |

x + 4z = 1

24x - 4z = 8

___________+

25x = 9

x = 9/25

Subsitution 1

2x + y = 1

2(9/25) + y = 1

18/25 + y = 1

y = 1 - 18/25

y = 25/25 - 18/25

y = 7/25

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