Differentiating the function
... g(x) = 5^(1+x)
we get
... g'(x) = ln(5)·5^(1+x)
Then the linear approximation near x=0 is
... y = g'(0)(x - 0) + g(0)
... y = 5·ln(5)·x + 5
With numbers filled in, this is
... y ≈ 8.047x + 5 . . . . . linear approximation to g(x)
Using this to find approximate values for 5^0.95 and 5^1.1, we can fill in x=-0.05 and x=0.1 to get
... 5^0.95 ≈ 8.047·(-0.05) +5 ≈ 4.598 . . . . approximation to 5^0.95
... 5^1.1 ≈ 8.047·0.1 +5 ≈ 5.805 . . . . approximation to 5^1.1
Answer:
slope = 
Step-by-step explanation:
Calculate the slope m using the slope formula
m = 
with (x₁, y₁ ) = (- 4, 1) and (x₂, y₂ ) = (0, 2) ← 2 points on the line
m =
=
= 
Answer:
I think its 6.40 but I'm not sure.
Answer:
a) x is the independent and y in the dependent
b) y=4
Step-by-step explanation:
b.) How much of the trail mix remains after you eat 6 servings?
Substitute 6 into the x variable.
y=16-2(6)
y=4
Answer:
diagram pls
then I can answer this question