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Sophie [7]
2 years ago
9

Elevator is accelerating upward 3.5 M/S2 and has a mass of 300 KG. The force of gravity is 2940 N. What is the tension force pul

ling elevator up?
Physics
1 answer:
forsale [732]2 years ago
8 0

Answer:

T = 3990 N

Explanation:

The free body diagram for the elevator consists of a tension force pointing up, and its weight pointing down. So the elevator's net force is:

F = T - 2940N

ad at the same time, using Newton's second law, we have that this net force should equal the elevator's mass (300 kg) times its acceleration (a):

T - 2940N = 300kg (3.5m/s^2)

then

T = 2940 N + 1050 N

T = 3990 N

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30grams

Explanation:

If a reaction starts with 30grams then the reaction should end with 30grams.

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A parallel-plate capacitor is connected to a battery. After it becomes charged, the capacitor is disconnected from the battery a
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Answer:

The potential difference between the plates increases

Explanation:

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q = CV         (1)

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V = \frac{qD}{A\epsilon_{o}}

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4 0
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The components of the net force on the cart is determined as 67.66 N.

<h3>Component of net force on the cart</h3>

The component of net force on the cart is determined by resolving the forces into x and y -components.

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T2 = 40 N

T1x = -30cos(0) = 30 N

T1y = 30sin(0) = 0

T2x = 40 x cos(30) = 34.64 N

T2y = 40 x sin(3) = 20 N

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∑Y = 0 + 20 N = 20 N

<h3>Resultant force</h3>

R = √(64.64² + 20²)

R = 67.66 N

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