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1 year ago

Is horsepower the only thing to be considered when purchasing a piece of equipment?Explain.

Physics

2 answers:

Novosadov [1.4K]1 year ago

8 0

Answer:

Mostly yes

Explanation:

But you should consider,brand value, material used and lasting of the equipment also

1HP=720W

HP stands for horsepower

It's mostly used in pumps

Juli2301 [7.4K]1 year ago

3 0

Not necessarily. It should definitely be a factor, but the age of the piece should be in question as well as the brand, materials used and how fuel-efficient it is.

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(a) Calculate the magnitude of the gravitational force exerted on a 445-kg satellite that is a distance of 1.77 earth radii from

victus00 [196]

Answer:

a)1396.52 N

b)1396.52 N

c) $a_{satellite}= 3.13 m/sec^2$

d) $a_{earth}=2.32\times10^{-22} m/s^2$

Explanation:

The force experienced by the satelite is giveb by

$F= \frac{Gm_{satellite}m_{earth}}{r^2} \\$

m_{satellite}= 445 Kg

m_{earth}= 6×10^24 Kg

radius r= 1.77Re= 1.77×6.38×10^6 m

now putting values we get

$F= \frac{6.67\times10^{-11}(445)(6\times10^24)}{(1.77\times6.38\times10^6)^2}$

⇒F= 1396.52 N

now,

$a_{satellite}= \frac{F}{m_{satellite}}$

$a_{satellite}= \frac{1396.52}{445}$

$a_{satellite}= 3.13 m/sec^2$

also,

$a_{earth}= \frac{F}{m_{earth}}$

$a_{earth}= \frac{1396.52}{(6\times10^24)}$

$a_{earth}=2.32\times10^{-22} m/s^2$

3 0

3 years ago

The ______________of matter depends upon how close the individual particles are together.

Simora [160]

The state of matter depends upon how close the individual particles are together

3 0

3 years ago

A vicious dog is pulling his owner with 150N of force . If the owner is dragged 40 meters , how much work did the dog do ?

Angelina_Jolie [31]

Afor:6000Nm

Explanation: work=force×distance

Work=150×40

Work=6000Nm

4 0

2 years ago

You perform the Hooke's Law experiment and create a plot of Displacement vs. Force. You add a linear fit and find the following

balandron [24]

Answer: 0.192 N/m

Explanation:

Well, generally when a Hooke's Law experiment is performed the plot is in fact Force vs Displacement, being the Force (in units of Newtons) in the Y-axis and the Displacement (in units of meters) in the X-axis.

In addition, if we add a linear fit the resultant equation will be the Line equation of the form:

$Y=mX+b$

Where $m=\frac{Y_{2}-Y_{1}}{X_{2}-X_{1}}$ is the slope and $b$ is the point where the line intersects the Y-axis.

So, if the equation is:

$Y=0.192X+0.011$

The slope of this line is $0.192 N/m$ which is also the spring constant $k$ .

7 0

2 years ago

A car of mass 998 kilograms moving in the positive y–axis at a speed of 20 meters/second collides on ice with another car of mas

goldfiish [28.3K]

<span> Let’s determine the initial momentum of each car.
#1 = 998 * 20 = 19,960
#2 = 1200 * 17 = 20,400

This is this is total momentum in the x direction before the collision. B is the correct answer. Since momentum is conserved in both directions, this will be total momentum is the x direction after the collision. To prove that this is true, let’s determine the magnitude and direction of the total momentum after the collision.

Since the y axis and the x axis are perpendicular to each other, use the following equation to determine the magnitude of their final momentum.

Final = √(x^2 + y^2) = √(20,400^2 + 19,960^2) = √814,561,600

This is approximately 28,541. To determine the x component, we need to determine the angle of the final momentum. Use the following equation.

Tan θ = y/x = 19,960/20,400 = 499/510
θ = tan^-1 (499/510)

The angle is approximately 43.85˚ counter clockwise from the negative x axis. To determine the x component, multiply the final momentum by the cosine of the angle.

x = √814,561,600 * cos (tan^-1 (499/510) = 20,400</span>

3 0

2 years ago

Is horsepower the only thing to be considered when purchasing a piece of equipment?Explain.​

Is horsepower the only thing to be considered when purchasing a piece of equipment?Explain.