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2 years ago

Is horsepower the only thing to be considered when purchasing a piece of equipment?Explain.

Physics

2 answers:

Novosadov [1.4K]2 years ago

8 0

Answer:

Mostly yes

Explanation:

But you should consider,brand value, material used and lasting of the equipment also

1HP=720W

HP stands for horsepower

It's mostly used in pumps

Juli2301 [7.4K]2 years ago

3 0

Not necessarily. It should definitely be a factor, but the age of the piece should be in question as well as the brand, materials used and how fuel-efficient it is.

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Serhud [2]

Answer:

The correct option is: 4. its ionization energy decreases

Explanation:

Ionization energy refers to the energy required to pull a valence electron completely from the valence shell of a gaseous atom.

Now, in the periodic table of chemical elements, as we down a group, the atomic radius increases, so the effective nuclear charge experienced by the valence electron decreases. Therefore, the ionization energy decreases, down the group.

As we across a period, the atomic radius usually decreases, so the effective nuclear charge experienced by the valence electron increases. Therefore, usually the ionization energy increases, across the period.

Therefore, as the atomic radius increases, the effective nuclear charge experienced by the valence electron decreases and thus the ionization energy also decreases.

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3 years ago

In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5

kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

Slits separation, $d=2.2\times 10^{-5}\ m$

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})$

$\theta=2.34^{\circ}$

Hence, this is the required solution.

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4 years ago

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Marysya12 [62]

We know, F = k * q₁ * q₂ / r²

Substitute the known values,
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F = 315 * 10⁹ / 1.44

F = 218.75 * 10⁹ N

F = 2.1875 * 10¹¹ N [ Final Answer ]

Hope this helps!

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4 years ago

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ANSWER

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4 years ago

Is horsepower the only thing to be considered when purchasing a piece of equipment?Explain.​

Is horsepower the only thing to be considered when purchasing a piece of equipment?Explain.