Answer:
a)1396.52 N
b)1396.52 N
c)
d)
Explanation:
The force experienced by the satelite is giveb by

m_{satellite}= 445 Kg
m_{earth}= 6×10^24 Kg
radius r= 1.77Re= 1.77×6.38×10^6 m
now putting values we get

⇒F= 1396.52 N
now,



also,



The state of matter depends upon how close the individual particles are together
Afor:6000Nm
Explanation: work=force×distance
Work=150×40
Work=6000Nm
Answer: 0.192 N/m
Explanation:
Well, generally when a Hooke's Law experiment is performed the plot is in fact Force vs Displacement, being the Force (in units of Newtons) in the Y-axis and the Displacement (in units of meters) in the X-axis.
In addition, if we add a linear fit the resultant equation will be the Line equation of the form:

Where
is the slope and
is the point where the line intersects the Y-axis.
So, if the equation is:

The slope of this line is
which is also the spring constant
.
<span> Let’s determine the initial momentum of each car.
#1 = 998 * 20 = 19,960
#2 = 1200 * 17 = 20,400
This is this is total momentum in the x direction before the collision. B is the correct answer. Since momentum is conserved in both directions, this will be total momentum is the x direction after the collision. To prove that this is true, let’s determine the magnitude and direction of the total momentum after the collision.
Since the y axis and the x axis are perpendicular to each other, use the following equation to determine the magnitude of their final momentum.
Final = √(x^2 + y^2) = √(20,400^2 + 19,960^2) = √814,561,600
This is approximately 28,541. To determine the x component, we need to determine the angle of the final momentum. Use the following equation.
Tan θ = y/x = 19,960/20,400 = 499/510
θ = tan^-1 (499/510)
The angle is approximately 43.85˚ counter clockwise from the negative x axis. To determine the x component, multiply the final momentum by the cosine of the angle.
x = √814,561,600 * cos (tan^-1 (499/510) = 20,400</span>