Answer:
-3+2sqrt7
-3-2sqrt7
Step-by-step explanation:
x^2+6x-9=10
x^2+6x-9-10=0
x^2+6x-19=0
ax^2+bx+c=0
a=1 b=6 c=-19
As cannot be solved by completing square we will use quadratic equation
x= (-b+sqrt(b^2-4ac))/2a and x= (-b-sqrt(b^2-4ac))/2a
x= (-6+sqrt(6^2-4*-19))/2 and x= (-6-sqrt(6^2-4*-19))/2
x=(-6+sqrt(36+76))/2 and x=(-6-sqrt(36+76))/2
x=(-6+4sqrt7)/2 and x=(-6-4sqrt7)/2
x=(-3+2sqrt7) and x=(-3-2sqrt7)
x=2.29 and x= -8.29
Answer: 2, 2, 13, 13
Step-by-step explanation: Prime number are numbers that can divide without remainder, This means that 676 is divisible by 2, 2, 13, 13, numbers.
-x^2 + 4x + 12 = -3x + 24
-> x^2 - 7x + 12 = 0
-> (x-3)(x-4) = 0
-> x= 3 or 4
so y = 15 when x = 3, y = 12 when x = 4
Answer:
solve by substitution method
