List in order from GREATEST to LEAST. 54.83, 54.03, 54.833

Mathematics

2 answers:

Maurinko [17]3 years ago

8 0

Answer:

54.833→54.83→54.03

Answered By

Z.Khan,

India

Art [367]3 years ago

7 0

Answer:

54.833, 54.83, 54.03

Step-by-step explanation:

Compare the numbers starting from the tenths, since the whole numbers are all the same, then the hundredths and so on.

54.830 (This is the second least since its thousandth is smaller)

54.030 (This is the least since its tenth is already the smallest)

54.833 (This is the greatest since it's digits are the largest even until the thousandth)

You might be interested in

Which of the following is a true statement about the equation y = -7/8x + 10

Greeley [361]

Answer:

Step-by-step explanation:

y = -7/8x - 10

in y = mx + b form, which is what this is in, the slope can be found in the m position

y = mx + b

y = -7/8x - 10

so u have slope (m) = - 7/8 <====

the slope is not 10

the graph will not pass thru the origin

this equation does not represent a proportional relationship

4 0

3 years ago

One of our brainliest, Konrad509, made this:

Reil [10]

$\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x$

A=10, B=11, C=12, etc.

$\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2$

$121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0$

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that $x\in\mathbb{N}$ . Moreover we can deduce that $x\geq19$ since there is $J$ and $J=19$ .