Step-by-step explanation:
step 1. (1) 5a +8c +4p = 57
(2) 9a +8c + 7p = 89
(3) 8a + 4c + 5p = 68.
step 2. this is a 3 variable system. solve the system.
step 3. eliminate c from (1) and (2) and also from (2) and (3). so you now have 4a + 3p = 32 and 7a + 3p = 47. now you have a two variable system
step 4. eliminate p by subtracting: 3a = 15 so a = 5.
step 5. if a = 5 then p = 4 ( plug into step 3)
step 6. if a = 5, p = 4, then c = 2 (plug into step 1).
step 7. apples = 5, pears = 4, cherries = 2.
<h3>The solution is (1, -3) or (-1, -3)</h3>
<em><u>Solution:</u></em>
Given that,
We have to find the solution (x, y)
<em><u>Substitute eqn 2 in eqn 1</u></em>
Thus, we get,
x = 1
x = -1
Thus the solution is (1, -3) or (-1, -3)
A) x<-2 and x<0 , the have the same part x<-2, so it has a solution
B) x≤ 0 and x<span> ≥0, the have the same part x=0
C)x<0 and x>0 , the do not have points that belong both inequalities , so
C has no solutions</span>
