What are the roots of 2x^2+10×-48=0

1 answer:

8 0

X=-8,3.
divide all terms by the two in the first term to get x^2+5x-24=0. Then find the factors. To do so, find what two numbers can be multiplied to get 24, and whether those two numbers can be added or subtracted to get the middle term (5). Since 8x(-3)=24 and 8-3=5, (x+8) and (x-3) are the factors. Then set the factors equal to zero. Add or subtract these numbers to the other side of the equation and you then get x=-8,3. These are the roots.

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The function $f(x)$ is given by

$f(x)=2x^{2} +4$

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To determine the value of $f(g(x))$ , let us first substitute the value of $g(x)$ .

Thus, we get,

$f(g(x))=f(\sqrt{3x^{3} } )$

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$f(g(x))=6x^{3} +4$

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So discriminant is being counted from that equation:
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