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2 years ago

QUESTION #1 - Probability

Mathematics

1 answer:

Olin [163]2 years ago

7 0

Answer:

Step-by-step explanation:

Probability of 3 on a cube: 1 / 6

Probability of 9 from cards 1-10: 1/10

1/6 x 1/10 = 1/60

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3 years ago

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4t+14=6t/5+7 what is the answer

Oliga [24]

4t+ 14= 6t/5+ 7
⇒ 4t+ 14= 6/5t+ 7
⇒ 4t -6/5t= 7 -14
⇒ (4 -6/5)t= -7 (distributive property)
⇒ 14/5t= -7
⇒ t= -7/ (14/5)
⇒ t= -5/2
⇒ t= -2.5

Final answer: t= -2.5~

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3 years ago

The tail on Alex dog is 5 1/4 inches long. This length is between which two inch-marks on ruler?

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That with be 38/1 inch you welcome have nice week

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3 years ago

Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a

Sladkaya [172]

Answer:

$y=(\ln{x})^2$

point of extremity: (1,0)

vertical asymptote: along the y-axis (x = 0)

point of inflection: (e,1)

Solution:

Although all these points can be directly observed from the graph below, but these are the analytical solutions if you're curious!

1) Extreme point can be found by differentiating 'y' once and equating to zero. solving for x:

$\dfrac{dy}{dx}=\dfrac{dy}{dx}((\ln{x})^2)$

$\dfrac{dy}{dx}=2\ln{x}\left(\dfrac{1}{x}\right)$

substitute dy/dx = 0, and solve for x

$0=2\ln{x}\left(\dfrac{1}{x}\right)$

$0=2\ln{x}$

$x=e^0$

$x=1$

use this value of x back in y, to find the y-coordinate of the extreme point

$y=(\ln{1})^2$

$y=0$

The extreme point = (1,0)

2) Differentiate y twice to find the inflection point.

$\dfrac{dy}{dx}=2\ln{x}\left(\dfrac{1}{x}\right)$

$\dfrac{d^2y}{dx^2}=2\ln{x}\left(-\dfrac{1}{x^2}\right)+\left(\dfrac{1}{x}\right)\left(\dfrac{2}{x}\right)$

$\dfrac{d^2y}{dx^2}=\dfrac{2}{x^2}\left(-\ln{x}+1}\right)$

substitute d2y/dx2 = 0, and solve for x

$0=\dfrac{2}{x^2}\left(-\ln{x}+1}\right)$

$0=-\ln{x}+1$

$\ln{x}=1$

$x = e$

use this value of x back in y, to find the y-coordinate of the inflection point

$y=(\ln{e})^2$

$y=1$

The extreme point = (e,1)

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3 years ago

A membership to the local gym costs $40 and then $2 per visit. What is the maximum number of visits that can be made for $90? Is

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2 years ago

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