The actual cost to the store = $140
Percentage of markup = 25%
Amount of markup in cost = (25/100) * 140 dollars
= 35 dollars
Then
Sell price in the store = (35 + 140) dollars
= 175 dollars
So the sell price of the product at the store after addition of the markup price will be $175.
Answer:
N(x) = 40 - 2x
P(x) = -2x² + 52 x - 240
maximum profit = 13
Step-by-step explanation:
given data
feeder cost = $6
average sell = 20 per week
price = $10 each
solution
we consider here price per feeder = x
and profit per feeder id here formula = x - 6
so that here
total profit will be
P (x) = ( x - 6 ) Nx
here N(x) is number of feeders sold at price = x
so formula for N (x) is here
N(x) = 20 - 2 ( x - 10 )
N(x) = 40 - 2x
so that
P(x) = (x-6) ( 40 - 2x)
P(x) = -2x² + 52 x - 240
since here
a = -2
b = 52
c = -240
a < 0
so quadratic function have maximum value of c -
so it will be
maximum value = -240 -
maximum value = 98
so here maximum profit attained at
x = 
x = 
x = 13
maximum profit = 13
Answer:
Is an acute angle. Acute angle should be 90 degrees
Step-by-step explanation:
The range of the function is 
Explanation:
The function is 
The domain of the function is 
We need to find the range of the function.
The range can be determined by substituting the values of domain in the function.
Thus, the range of the function when the domain is -3 is given by



Thus, the range is -19 when 
The range of the function when the domain is 0 is given by



Thus, the range is -4 when 
The range of the function when the domain is 4 is given by



Thus, the range is 16 when 
Thus, the range of the function is
when their corresponding domain is 
Arranging the range in order from least to greatest is given by

Hence, the range of the function is 
The center of the circle is f(6,10)