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yulyashka [42]
3 years ago
13

The area of a rectangle is 30m11n5 square units. If the length of the rectangle is 6m^n2 units, how many units wide is

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0

Given:

The area of a rectangle = 30m^{11}n^{5}

Length of the rectangle = 6m^4n^2

To find:

The width of the rectangle.

Solution:

Area of a rectangle is:

A=l\times w

Where, l is the length and w is the width of the rectangle.

Divide both sides by l.

\dfrac{A}{l}=w

w=\dfrac{A}{l}

On substituting the given values, we get

w=\dfrac{30m^{11}n^{5}}{6m^4n^2}

w=5m^{11-4}n^{5-2}           [\because \dfrac{a^m}{a^n}=a^{m-n}]

w=5m^{7}n^{3}

Therefore, the correct option is A.

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The points (-3,-1) and (-3,5) are adjacent vertices of a rectangle. Two of the sides of the rectangle have a length of 8 units.
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Answer:

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Step-by-step explanation:

Data

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Process

1.- Calculate the distance between A and B

dAB = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

x1 = -3     y1 = -1

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-Substitution

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- Conclusion

The diagonal of the rectangle measures 10 units

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