Answer:
Every physics student learns Newton's three laws of motion. It's tempting to consider that these are three separate and independent laws. That's not so. Both the first and third laws may be mathematically derived from the second law, as we will show.
The fact that the first law may be derived from the second has long been known. The second law,Fnet=ma, tells us that the net (vector sum) of all forces acting on a body is equal to the product of the body's mass and its vector acceleration. When the acceleration is zero, the net force must be zero. This is exactly the content of the first law.
Let's first consider the case of two bodies in contact. Each exerts a force on the other at the interface, or point of contact, where the bodies touch. If that point or interface is treated as a "body" of mass zero, then Newton's second law tells us thatFnet=0a, soFnet= 0. So the net force on a body of zero mass is always zero, whatever forces act upon it. Therefore if only two forces act on a body, they must add to zero, and therefore must be equal size and oppositely directed. This establishes Newton's third law.
Explanation:
Hope this helps
Answer:
Start
Input n, 2
Calculate if (n%2==0) then is divisible else not divisible
Output number is divisible or not
Stop
Explanation:
Answer:
Computer Science is the study of the existing things and programming language to acquire knowledge in that field
Computer engineering is applying the knowledge to invent new things
Explanation:
Computer Science is the study of the existing things and programming language to acquire knowledge in that field
Computer engineering is applying the knowledge to invent new things
If we want to accomplish any task , first you should know how to achieve that task and you should have some knowledge to do that task. Computer Science basically deals with acquiring knowledge in the are of computers.
Computer engineering is the engineering things based on the facts we have alreday
You should state the language you're using in these types of questions; here's an example in C++.
bool onOff = true;
if (onOff)
onOff = false;
else
onOff = true;
