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Mathematics

1 answer:

Anon25 [30]3 years ago

6 0

Answer:

x = 26

Step-by-step explanation:

1. Information

One can partition this figure into three different parts, two congruent triangles, and one rectangle. To find the value of x, one has to find the base of the two triangles, and then the base of the rectangle. Since opposite sides are congruent, the base of the rectangles is 10. To find the base of the triangle, one has to use the Pythagorean theorem.

2. Base of the rectangle

Again, opposite sides are congruent, hence the base of the rectangle is equivalent to the top part. Hence the base is 10.

3. Base of the triangle

Use the Pythagorean theorem;

$a^{2}+b^{2} = c^{2}\\a-leg\\b-leg\\c-hypotenuse$

Substitute in the given value and solve

$a^{2}+15^{2} = 17^{2}\\a^{2} + 225 = 289\\a^{2} = 64\\a = 8$

4. Finding x

There are two congruent trinagles, hence one has to add the base of the triangle twice. The equation will be

x = base_of_triangle + base_of_rectagle + base_of_triangle

x = 8 + 10 + 8

x = 26

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Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then

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Answer:

It is proved that $\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Step-by-step explanation:

Given vector field,

$F=P\uvec{i}+Q\uvec{j}+R\uvec{k}$

Where,

$P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}$

To show,

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Consider,

$\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}$

$\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}$