Answer:
EF = 
≈ 5.83
Step-by-step explanation:
Calculate EF using the distance formula
d = 
with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)
EF = 
= 
= 
= ≈ 5.83 ( to 2 dec. places )
500 because the 2 in the tens spot is less than five so therefore you keep the 5 in the hundreds spot the same
Answer:
100 is the median for te above observations
<h2><em><u>HOPE</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>HELPED</u></em><em><u> </u></em></h2>
The number of miles for which the car has been driven if one paid $122.50 as in the task content is; 2.5 miles.
<h3>For how many miles was the car driven?</h3>
It follows from the task content that the total amount paid was; $122.50.
Hence, after subtraction the constant charges, for the day and for gas, the remainder is;
$122.50 - $50 - $35
= $37.50.
Ultimately, if the charge per mile is $15, then the number of miles driven is; $37.50/$15
= 2.5 miles.
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