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asambeis [7]
2 years ago
5

What is the solution to

Mathematics
2 answers:
Rasek [7]2 years ago
6 0

Answer:

The answer is choices C.

Step-by-step explanation:

Let's solve your inequality step-by-step.

2x+8<3x−4

Step 1: Subtract 3x from both sides.

2x+8−3x<3x−4−3x

−x+8<−4

Step 2: Subtract 8 from both sides.

−x+8−8<−4−8

−x<−12

Step 3: Divide both sides by -1.

−x/-1<−12/-1

x>12

Aliun [14]2 years ago
5 0

Answer:

A

Step-by-step explanation:

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Basically if 1 bought i gallon its 3.60

2= 7.2 dollars and so forth

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Step-by-step explanation:

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3 years ago
Which mathematical property is demonstrated 40•(25•74) = (40•25)•74
Sindrei [870]
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6 0
3 years ago
Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.
Flauer [41]

Answer:

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

Step-by-step explanation:

Given

\sqrt{128a^{6}b^{13}}

Required

Solve

\sqrt{128a^{6}b^{13}}

The expression can be split to:

\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}

So, we have:

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}

Rewrite as:

\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2}  * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

5 0
2 years ago
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