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malfutka [58]
2 years ago
13

I AM STRUGGLING!!! PLEASE HELP ME!!

Mathematics
1 answer:
Butoxors [25]2 years ago
4 0

Answer:

The answer would b 6.59 inches

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Titus works at a hotel. Part of his job is to keep the complimentary pitcher of water at least half full and always with ice. Wh
Zigmanuir [339]

Answer: b. 160

Step-by-step explanation: just took the test

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3 years ago
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adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
3 years ago
Answer pls no link I need help
Misha Larkins [42]

Answer:

20

Step-by-step explanation:

the whole angle needs to be 180 degrees 180-100=80 80-20=60 20×3=60 60+20=80 80+100=180

8 0
3 years ago
I need help what times what equals 104
forsale [732]
1 times 104
2 times 52
4 times 26
8 times 13
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3 years ago
You are playing a video game called "Zombie Attack."
Volgvan
120 + 5k = 350
120 + 5k - 120 = 350 - 120
5k = 230
5k/5 = 230/5
K = 46
6 0
3 years ago
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