Question

A spinner is divided into 4 equal sections numbered 1 through 4. It is spun twice, and the numbers from each spin are added.

Answer 1

Answer:

0.625

Step-by-step explanation:

Since there are 4 options each time the spinner is spun, there are a total of $4\cdot 4=16$ non-distinct sums possible when we spin it twice.

Out of these, the possible sums that meet the condition (less than 6) are 2, 3, 4, and 5 (since the smallest sum possible is 1+1=2).

Count how many ways there are to achieve each of these sums:

$1+1=2\\\\1+2=3\\2+1=3\\\\2+2=4\\1+3=4\\3+1=4\\\\2+3=5\\3+2=5\\4+1=5\\1+4=5$

Totally there are 10 ways to achieve a sum less than 6. Therefore, the desired probability is $\frac{10}{16}=\frac{5}{8}=\boxed{0.625}$