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MrMuchimi
3 years ago
14

12+6 over N What is the value of when N= 2? A.6 B.9 C.12 D.18

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

Answer:

thank you to your question i dont know if my

answer is correct this is my answer letter B

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I need some help please
Nataliya [291]

Answer:

25π

Step-by-step explanation:

4 0
3 years ago
Jaime hiked for 3 days across an island. He started at the shoreline, which is at an elevation of O feet.
Gre4nikov [31]

Answer:

  • D. 4120 feet

Step-by-step explanation:

<u>Jamie lost on the third day:</u>

  • 2150 + 1970 = 4120 feet

Correct option is D.

4 0
3 years ago
Read 2 more answers
A retailer sold a mobile set for Rs 8,330 and made a loss of 2%. For what price should he sell it to gain 7%?​
Vanyuwa [196]

Answer:

New Price = Rs. 9095

Step-by-step explanation:

Selling Price = Rs 8,330

Loss = 2%

<u><em>Costing Price:</em></u>

Let CP be x

Then,

x = 8,330+0.02 x

=> x-0.02x = 8330

=> 0.98x = 8330

=> x = Rs. 8,500

So, Costing Price is Rs 8,500

<u><em>Now, Profit for 7% profit %age:</em></u>

Profit = 0.07 * 8500

Profit = Rs 595

<u><em>New Price:</em></u>

New Price = CP + Profit

New Price = 8500+595

New Price = Rs. 9095

6 0
3 years ago
Sue has 4 pieces of wood. the lengths of her pieces of wood are 1/3 foot, 2/5 foot, 3/10 foot, and 1/4 foot. Which piece of wood
Leya [2.2K]
1/3 = 20/60
2/5 = 24/60
3/10 = 18/60
1/4 = 15/60

The shortest is the wood piece with the length of 1/4 ft
6 0
3 years ago
Read 2 more answers
Trayectoria de un balón. El siguiente grafico ilustra la trayectoria d en balón de fútbol. La altitud máxima de recorrido del ba
jonny [76]

Answer:

C) Ascenso 6,34 m; Descenso 17,66 m

Step-by-step explanation:

La altitud máxima que recorre la pelota con respecto al suelo, h = 9 metros

La forma general de la ecuación de una parábola es y = a·x² + b·x + c

La velocidad vertical inicial de la pelota, u_y = √(2·g·h)

∴ u_y = √(2 × 9.81 × 9) ≈ 13.288

La velocidad vertical inicial de la pelota, u_y ≈ 13.288 m/s

El tiempo de vuelo de la pelota = 2 × u_y/g ≈ 2 × 13.288/9.81 = 2.709

El tiempo que tarda el balón en alcanzar los 7 metros sobre el suelo se indica de la siguiente manera;

s = u_y·t + (1/2)·g·t²

∴ 7 ≈ 13.288·t - (1/2)×9.81×t²

13.288·t - (1/2)×9.81×t² - 7 ≈ 0

Factorizar con el uso de una calculadora gráfica da;

t ≈ 0.716 s, or t ≈1.993t

Dado que la velocidad horizontal es constante, verificamos entre las opciones dadas una que proporcione los valores de la velocidad horizontal, vₓ, tanto para el ascenso como para el descenso, es decir, para ambos valores de 't' de la siguiente manera;

De las opciones de respuesta dadas, la velocidad horizontal es aproximadamente constante para la única opción 'C', donde tenemos;

vₓ = 6.34/0.716  ≈ 8.85

vₓ = 17.66/1.993 ≈ 8.86

El rango horizontal, d = 8.85 × 2.709 ≈ 24

La distancia horizontal de la pelota durante el ascenso cuando la pelota alcanza una altura de 7 m = 6.34 m, durante el descenso, la distancia horizontal = 17.66 m

La ecuación de una parábola (la trayectoria de la pelota) se puede presentar de la siguiente manera;

y = a·(x - h)² + k

Dónde;

(h, k) = La coordenada del vértice

k = 9

En el origen, (x, y) = (0, 0)

Por lo tanto;

0 = a · (0 - h) ² + 9

a · h² = -9

En y = 7. x = 6.34

∴ 7 = a · (6.34 - h) ² + 9

a = -2 / ((6,34 - h) ²)

a = -2 / ((17,66 - h) ²)

(6,34 - h) ² = (17,66 - h) ²

h²-12,68 · h + 40,1956 = h² -35,32 · h +311,8756

h² -35,32 · h + 311,8756 - (h²-12,68 · h + 40,1956) = 0

-35,32 · h + 12,68 · h = 40,1956 - 311,8756

h = (40,1956 - 311,8756) / (- 35,32 + 12,68)

a = -2 / ((6,34 - 12) ²) ≈ -0,06243054601

La trayectoria de la pelota es y = -0.06243054601 · (x - 12) ² + 9

Por tanto, la mejor opción correcta que cumpla con los parámetros dados es la opción C) Ascenso 6,34 m; Descendencia 17.66 m.

7 0
3 years ago
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