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Fudgin [204]
3 years ago
6

Janna works at a lab with a huge circular particle accelerator. It has a radius of 4 kilometers. What is the accelerator's diame

ter?​
Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Step-by-step explanation:

since it is a circle the diameter is two times larger than radius.So 4×2=8km

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How do i simplify 2a 3(4a-5)?
____ [38]
2a 3x4a +3x-5
2a+12a-15
14a-15
i think thats the answer
8 0
3 years ago
A square garden has a diagonal length of 18 feet. What is the area of the garden?
velikii [3]

Answer:

162 square feet

Step-by-step explanation:

Let the side lengths of the square be l feet each.

Then the diagonal together with any two sides forms an isosceles right triangle.

We can apply the Pythagoras Theorem, which says that, the sum of the squares of the two shorter legs equals the square of the hypotenuse ( the diagonal) in this case.

Divide both sides by

The area of the square garden is 162 ft²

The number of 1 foot by 1 foot square planter boxes that can fill this garden is

7 0
2 years ago
1. A sphere is sliced so that the cross section does not intersect the center of the sphere.
stich3 [128]
1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,

A = L*H = 12*6 = 72 cm^2

3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).

Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2

4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.

Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
8 0
3 years ago
Read 2 more answers
How do you solve for b and c?
dangina [55]
C:
6*2 = 2.5c
c = 4.8

b:
Cannot be solved until the measure of one other angle in the X is added.
6 0
3 years ago
3x - 5y = 14 and – 2x + 2y = 0
zubka84 [21]

Answer:

x=5.6

y=-5.6

Step-by-step explanation:

3x - 5y = 14 Equation 1

– 2x + 2y = 0 Equation 2

Simultaneous equation can be solved either through elimination method or substitution method. But we use elimination method for this question

Multiply equation 1 by -2 (the coefficient of x in equation 2) and multiply equation 2 with 3 (the coefficient of x in equation 1), so that x will have the same coefficient in the new equations, and easy to eliminate

-2(3x - 5y = 14)

-6x+10y=-28 Equation 3

3(– 2x + 2y = 0)

-6x+6y=0 Equation 4

Subtract equation 4 from 3 to eliminate x

-6x+10y=-28

-6x+6y=0

-6x-(-6x)=-6x+6x=0

10y-6y=5y

-28-0=-28

5y=-28

y=-28/5

y=-5.6

Substitute for y in equation 2

– 2x + 2y = 0

– 2x + 2(-5.6) = 0

-2x-11.2=0

-2x=11.2

x=-11.2/2

x=5.6

7 0
3 years ago
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