1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RUDIKE [14]
3 years ago
12

The product of x and the sum of 6 and 8 times the square of x

Mathematics
1 answer:
fiasKO [112]3 years ago
7 0

"·" - product

"+" - sum

x² - square of x

Answer: x · (6 + 8 · x²) = x(6 + 8x²)

You might be interested in
What is the equation of the line?
umka2103 [35]

Answer:

y=2x+8

Step-by-step explanation:

All of the choices are in slope-intercept, or y=mx+b form where m is the slope and b is the y intercept. Therefore if the slope is 2, and the y intercept is 8 the equation should be y=2x+8.

3 0
3 years ago
Find P on AB that is 2/3 of the distance from A(-3,-5) to B(9,4).
Ludmilka [50]

A line segment can be divided into ratios.

<em>The coordinate of P on line segment AB is (5,1)</em>

Given

A = (-3,-5)

B = (9,4)

The position of P from A to B is:

P_A = \frac 23

So, from P to B would be:

P_B =1 -  \frac 23

P_B = \frac 13

So, the ratio is:

m : n = \frac 23 : \frac 13

Simplify

m : n = 2 :1

<u>The coordinate of point P is:</u>

P = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})

So, we have:

P = (\frac{2 \times 9 + 1 \times -3}{2 + 1},\frac{2 \times 4 + 1 \times -5}{2 + 1})

P = (\frac{15}{3},\frac{3}{3})

P = (5,1)

<em>Hence, the coordinate of P is (5,1)</em>

Read more about line ratios at:

brainly.com/question/8847082

8 0
3 years ago
6 + (9 − 1) 2 ÷ 4 ⋅ 1 over 2 whole to the power of 4
Bas_tet [7]

Answer:

625

Step-by-step explanation:

1. parenthesis first, so it simplifies to ((6+(8)2÷4*1)/2)^4

2. pemdas says that multiplication and division go before addition and subtraction, so ((6+(8)2÷4*1)/2)^4 becomes ((6+16÷4*1)/2)^4 ---> ((6+4)/2)^4

3. then simplify inside of the parenthesis, so it becomes 5^4, which is 625

6 0
3 years ago
Is 9 a solution to the equation 21=3p-5? Show work
Dmitry_Shevchenko [17]

Answer:

No

Step-by-step explanation:

21 = 3p - 5

<u>Step 1</u> : Add 5 on both sides

21 + 5 = 3p

26 = 3p

3p = 26

<u>Step 2</u> : Divide 3 on both sides

p = 26/3

Hence, the solution of the given equation is 26/3, not 9.

4 0
2 years ago
Which lines are perpendicular to the line y – 1 = (x+2)? Check all that apply.
Ilya [14]

Answer:

none of them

Step-by-step explanation:

Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.

line 1:  

y – 1 = (x+2)

y = x + 3

slope of line 1 = 1

line 2:  

y + 2 = –3(x – 4)

y + 2 = -3*x + 12

y =  -3*x + 10

slope of line 2 = -3

m1*m2 = 1*(-3 ) = -3

They are not perpendicular

line 3:  

y − 5 = 3(x + 11)

y − 5 = 3*x + 33

y = 3*x + 38

slope of line 3 = 3

m1*m3 = 1*3 = 3

They are not perpendicular

line 4:  

y = -3x –  

slope of line 4 = -3

m1*m4 = 1*(-3 ) = -3

They are not perpendicular

line 5:  

y = x – 2

slope of line 5 = 1

m1*m5 = 1*1 = 1

They are not perpendicular

line 6:  

3x + y = 7

y = -3x + 7

slope of line 6 = -3

m1*m6 = 1*(-3 ) = -3

They are not perpendicular

5 0
4 years ago
Read 2 more answers
Other questions:
  • There are approximately 3.2
    12·1 answer
  • The ordered pair (a,b) satisfies the inequality y&gt;x+3. Which statement is true ?
    5·1 answer
  • Eight times a number equals the number increased by 504. find the number.
    12·1 answer
  • Find the quotient of 5 divided by7/8
    9·2 answers
  • Name an equivalent ratio for 1/2 with a denominator of 20
    7·2 answers
  • Find n(A) for the set A = {300, 301, 302, ..., 3000}
    9·1 answer
  • Solve 3x2 + 6x + 6 = 0. (5 points)
    6·2 answers
  • Solve (-6 - 4) = (-5) =
    15·1 answer
  • Help please I don’t get it
    7·1 answer
  • Can somebody please help me with number 2 and 5 its done today i will give brainliest
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!