16, because all the other numbers are divisible by 3.
Or it could be 6 because it only has one digit while the others have 2
yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy
-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)
9x³ - 19x² - 17 = (x - a)(x - b - ic)(x - b + ic)
Answer:
(-5.77, 6.46)
Step-by-step explanation:
15x + 9y = 45 ----------- i
9x + 8y = 12----------------ii
Multiply equation i by 9 the coefficient of x in equ ii
And equation ii by 15 the coefficient of x in equ I
9 x 15x + 9y = 45 ----------- i
15 x 9x + 8y = 12----------------ii
135x+81y = 405
135x+120y= 180
Subtract equation ii from I
135x-135x+81y-(+120y)= 405-180
-39y=225
y = 225/-39 = -5.77
Insert the value of y in equ i
15x + 9y = 45
15x+9(-5.77) = 45
15x-51.92=45
15x = 45+51.92
15x= 96.92
x = 96.92/15= 6.46
(x,y) = (-5.77, 6.46)
x = 6.92/15
Answer: the answer is indeed (4,8)
Step-by-step explanation:
