140/7=20. Which means they charge $20 per car.
60*20=$1200
Answer:
0.5 ; 0.475 ; 0.689 ; 0.4013
Step-by-step explanation:
Given that:
Rate of production of defective batteries p = 0.05
Number of batteries produced (n) = 10
The expected number of defective batteries = mean = n * p = 10 * 0.05 = 0.5 batteries
Variance of defective batteries :
Var(X) = n * p * q ; q = 1 - p
Hence,
Var(X) = 10 * 0.05 * 0.95 = 0.475
Standard deviation (X) = sqrt(variance) = sqrt(0.475) = 0.689
Probability that atleast 1 battery is defective :
Using the binomial probability function
P(x ≥ 1) = 1 - p(x = 0)
= 1 - q^n
= 1 - 0.95^10
= 1 - 0.59873693923837890625
= 0.40126306076162109375
= 0.4013
Answer:
18a-12b+6c
Step-by-step explanation:
We have got 6 common in this factor 6(3a-2b+c)
So,in order to expand it we just need to multiply 6 with the everything in the bracket..
6×3a=18a
6×2b=12b
6×c=6c
If we arrange the factor after multiplying,then it stands like this 18a-12b+6c...
(Ans)
