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3 years ago

Which ecosystem has the greater amount of biodiversity?

Physics

1 answer:

suter [353]3 years ago

7 0

Answer: My big guess would be Tropical rainforests.

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On a spacecraft, two engines are turned on for 789 s at a moment when the velocity of the craft has x and y components of v0x =

ddd [48]

Answer:

Explanation:

Given

time for which spacecraft turned on is 789 s

$v_{0x}=5410 m/s$

$v_{0y}=8100 m/s$

$x=2.78\times 10^6 m$

$y=4.73\times 10^6 m$

we know $s=ut+\frac{at^2}{2}$

$2.78\times 10^6=5410\times 789+\frac{a_x(789)^2}{2}$

$2.78=4.268+a_x\times 0.622$

$a_x=-2.392 m/s^2$

For y component

$s=ut+\frac{at^2}{2}$

$4.73\times 10^6=8100\times 789+\frac{a_y(789)^2}{2}$

$4.73=6.39+a_y\times 0.622$

$a_y=-2.66 m/s^2$

4 0

4 years ago

Planets that are cold have only a small amount of gravity

Nonamiya [84]

There is no theoretical OR observational evidence for that statement.

4 0

4 years ago

Click through the images and select the model that best shows how J.J. Thomson envisioned the atom.

Alexandra [31]

Answer:

The first one with the big plus in the middle and negatively charged electrons around.

Explanation:

7 0

3 years ago

A lunch pail is accidentally kicked off a steel beam on a building under construction. Suppose the initial horizontal speed is 1

vichka [17]

1) 26.6 m

Along the horizontal direction, the lunch pail is moving with a uniform motion (constant speed), since there are no forces acting in this direction.

Therefore, the distance travelled horizontally after a time t is given by:

$d=v_x t$

where we know

$v_x = 1.50 m/s$ is the horizontal velocity

d = 3.50 m is the distance covered horizontally

Solving for t, we find the total time of the motion:

$t=\frac{d}{v_x}=\frac{3.50}{1.50}=2.33 s$

Now we know that the pail takes 2.33 s to fall to the ground. We can now consider the vertical motion of the pail, which is a free fall motion, so the vertical displacement is given by the equation

$s=ut+\frac{1}{2}at^2$

where, taking downward as positive direction:

u = 0 is the initial vertical velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity

Substutting t = 2.33 s, we find how fat the pail has fallen:

$s=\frac{1}{2}(9.8)(2.33)^2=26.6 m$

2) 10.7 m

In this case, we know instead the vertical displacement:

$s=2.50\cdot 10^2 m = 250 m$

Therefore, we can use the same equation again

$s=ut+\frac{1}{2}at^2$

To find the total time of motion:

$t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(250)}{9.8}}=7.14 s$

We know that along the horizontal direction, the velocity is constant:

$v_x = 1.50 m/s$

So, the horizontal distance covered in this time is

$d=v_x t = (1.50)(7.14)=10.7 m$

6 0

4 years ago

Can someone please help on this one?

zhuklara [117]

Please READ Newton's first law of motion, and you'll see how nicely it explains that fact.

8 0

4 years ago