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Readme [11.4K]
2 years ago
6

In an inelastic collision, a steel ball of mass 200 g was hit hard into a large ball of dough of mass 700 g. The velocity of the

steel ball was 25 m/s. After the collision, the steel ball was stuck in the dough, and this combined system rolled for some time. What was the velocity of the system of the steel ball and dough after the collision?A) 5.6 m/sB) 7.5 m/sC) 8.8 m/sD) 11.1 m/s
Physics
1 answer:
Tcecarenko [31]2 years ago
4 0

Answer:

Velocity after collision will be 5.56 m/sec

So option (a) will be correct answer

Explanation:

Mass of steel ball m_1=200gram=0.2kg

Speed of steel ball before collision v_1=25m/sec

Mass of large ball m_2=700gram=0.7kg

Velocity of large ball v_2=0m/sec

According to conservation of momentum

m_1v_1+m_2v_2=(m_1+m_2)v

0.2\times 25+0.7\times 0=(0.7+0.2)v

v=5.56m/sec

So velocity after collision will be 5.56 m/sec

So option (a) will be correct answer

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Answer:

Distance, d is 86.1 meters.

Explanation:

Given the following data;

Time, t = 6.15secs

Velocity = 14m/s

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

Velocity = \frac{distance}{time}

V = \frac{d}{t}

d = Vt

Substituting into the above equation;

d = 14 * 6.15

d = 86.1m

Hence, the distance traveled by the boat is 86.1 meters.

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Answer:

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Explanation:

The formula of the Young's Double Slit experiment is given as follows:

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where,

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\lambda = \frac{(0.00453\ m)(0.00109\ m)}{8.61\ m}

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If you were to inject air into space what would have happen?

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