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Readme [11.4K]
2 years ago
6

In an inelastic collision, a steel ball of mass 200 g was hit hard into a large ball of dough of mass 700 g. The velocity of the

steel ball was 25 m/s. After the collision, the steel ball was stuck in the dough, and this combined system rolled for some time. What was the velocity of the system of the steel ball and dough after the collision?A) 5.6 m/sB) 7.5 m/sC) 8.8 m/sD) 11.1 m/s
Physics
1 answer:
Tcecarenko [31]2 years ago
4 0

Answer:

Velocity after collision will be 5.56 m/sec

So option (a) will be correct answer

Explanation:

Mass of steel ball m_1=200gram=0.2kg

Speed of steel ball before collision v_1=25m/sec

Mass of large ball m_2=700gram=0.7kg

Velocity of large ball v_2=0m/sec

According to conservation of momentum

m_1v_1+m_2v_2=(m_1+m_2)v

0.2\times 25+0.7\times 0=(0.7+0.2)v

v=5.56m/sec

So velocity after collision will be 5.56 m/sec

So option (a) will be correct answer

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Answer:

Part a)

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

q = 3.37 \times 10^{-4} C

Explanation:

As we know that electric force on electric charge is given as

F = qE

here we have

q = 1.6 \times 10^{-19}C

E = 153 N/C

now force is given as

F = (1.6 \times 10^{-19})(153) = 2.45 \times 10^{-17} N

Gravitational force on electric charge near surface of earth is given as

F_g = mg

F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N

now the ratio of two forces is given as

\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

Now the ball is balanced by the electric force and the force of gravity on it

so here we have

F_g = qE

mg = qE

(5.25 \times 10^{-3})(9.81) = q(153)

here we have

q = 3.37 \times 10^{-4} C

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3 years ago
If the half-life of iodine-131 is 8.10 days, how long will it take a 50.00 g sample to decay to 6.25 g?
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3 years ago
light waves are first transmitted through the ________ at the front of the eye and enter an opening called the ________ before s
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The transmission of light waves is usually done through cornea of the eyes, then move through another opening which is regarded as pupil before it will get to the retina.

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A playroom is 12 m2. The length of the room is 3 m. What is the width?
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The width of the playroom is 4 m
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3 years ago
a 0.145 kg baseball pitched at 39.0 m/s is hit on a horizontal line drive straight back toward the pitcher at 52.0 m/s. if the c
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consider the velocity towards the pitcher as positive

m = mass of the baseball = 0.145 kg

v₀ = initial velocity of the baseball = - 39 m/s

v = final velocity of the baseball = 52 m/s

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Using impulse-change in momentum equation

F t = m (v - v₀ )

F (3 x 10⁻³) = (0.145) (52 - (- 39))

F = 4398.33 N

3 0
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