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Readme [11.4K]
2 years ago
6

In an inelastic collision, a steel ball of mass 200 g was hit hard into a large ball of dough of mass 700 g. The velocity of the

steel ball was 25 m/s. After the collision, the steel ball was stuck in the dough, and this combined system rolled for some time. What was the velocity of the system of the steel ball and dough after the collision?A) 5.6 m/sB) 7.5 m/sC) 8.8 m/sD) 11.1 m/s
Physics
1 answer:
Tcecarenko [31]2 years ago
4 0

Answer:

Velocity after collision will be 5.56 m/sec

So option (a) will be correct answer

Explanation:

Mass of steel ball m_1=200gram=0.2kg

Speed of steel ball before collision v_1=25m/sec

Mass of large ball m_2=700gram=0.7kg

Velocity of large ball v_2=0m/sec

According to conservation of momentum

m_1v_1+m_2v_2=(m_1+m_2)v

0.2\times 25+0.7\times 0=(0.7+0.2)v

v=5.56m/sec

So velocity after collision will be 5.56 m/sec

So option (a) will be correct answer

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A soccer player kicks a soccer ball with a force of 1.8 N. If the mass of the ball is .43 kg. How fast will the ball accelerate?
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Explanation:

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3 years ago
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Which statements best describe the second stage of cellular respiration? Check all that apply.
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Select the correct answer.
kvasek [131]

Answer:

8.37×10⁻⁴ N/C

Explanation:

Electric Field: This is the ratio of electrostatic force to electric charge. The S.I unit of electric field is N/C.

From the question, the expression for electric field is given as,

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Where E = Electric Field, F = force experienced by the charged balloon, Q = Charge on the balloon.

Given: F = 8.2×10⁻² Newton, Q = 9.8×10 Coulombs = 98 Coulombs

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Hence the Electric Field of the charged balloon =  8.37×10⁻⁴ N/C

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2 years ago
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