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4 years ago

To determin the density of an empty plastic jug what would you measure

Physics

1 answer:

eduard4 years ago

6 0

Its mass and volume of the plastic used to make a jug.

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Which particles in an atom are acted upon by the strong force? A. Electrons and neutrons B. Neutrons and protons O C. Protons an

BARSIC [14]

$\large \sf \pmb{B) \: Neutrons \: and \: Protons}$

<em>Neutrons And Protons</em> is a particles in an atom and are acted upon by the strong force.

6 0

3 years ago

The Grinch is trying to push a 5000-kg sled up the side of Mount Crumpit (whose side make an angle of 60 degrees above the horiz

navik [9.2K]

Answer:

Explanation:

height lost h = 300 sin60

= 259.8 m .

gravitational potential energy = mgh

= 5000 x 9.8 x 259.8

= 1273 x 10⁴ J

Kinetic energy

= 1/2 mv²

= .5 x 5000 x 60²

= 900 x 10⁴ J

there is loss of kinetic energy = 373 x 10⁴ J.

This loss in energy is due to kinetic friction that came into action when the sled slipped downwards.

The lost energy is converted into heat energy or thermal energy.

8 0

4 years ago

Which of the following is a way in which earth material is returned to the surface?

kvv77 [185]

Answer:

Explanation:

soil

4 0

3 years ago

Read 2 more answers

Calculate the force of gravity on the 1.2-kg mass if it were 1.9×107 m above earth's surface (that is, if it were four earth rad

Anettt [7]

Answer:

Force of gravity, F = 0.74 N

Mass of an object, m = 1.2 kg

Distance above earth's surface, $d=1.9\times 10^7\ m$

Mass of Earth, $M=5.97\times 10^{24}\ kg$

Radius of Earth, $r=6.37\times 10^6\ m$

We need to find the force of gravity above the surface of Earth. It is given by :

$F=G\dfrac{mM}{R^2}$

R = r + d

R = 25370000 m

$F=6.67\times 10^{-11}\times \dfrac{5.97\times 10^{24}\ kg\times 1.2\ kg}{(25370000\ m)^2}$

F = 0.74 N

So, the force of gravity on the object is 0.74 N. Hence, this is the required solution.

5 0

4 years ago

A 98.0 N grocery cart is pushed 12.0 m along an aisle by a shopper who exerts a constant horizontal force of 40.0 N. If all fric

Digiron [165]

Answer:

9.8 m/s

Explanation:

The work done by the force pushing the cart is equal to the kinetic energy gained by the cart:

$W=K_f -K_i$

where

W is the work done

$K_f$ is the final kinetic energy of the cart

$K_i$ is the initial kinetic energy of the cart, which is zero because the cart starts from rest, so we can write:

$W=K_f$

But the work is equal to the product between the pushing force F and the displacement, so

$W=Fd=(40.0 N)(12.0 m)=480 J$

So, the final kinetic energy of the cart is 480 J. The formula for the kinetic energy is

$K_f=\frac{1}{2}mv^2$ (1)

where m is the mass of the cart and v its final speed.

We can find the mass because we know the weight of the cart, 98.0 N:

$m=\frac{F_g}{g}=\frac{98.0 N}{9.8 m/s^2}=10 kg$

Therefore, we can now re-arrange eq.(1) to find the final speed of the cart:

$v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(480 J)}{10 kg}}=9.8 m/s$

7 0

3 years ago