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Otrada [13]
4 years ago
12

Help with the following five problem please! For number 12 the teacher said 10 drops= 1 mm

Physics
1 answer:
Whitepunk [10]4 years ago
7 0

a 100mg dog ???

a 0.1 gram dogf ???

hmmm no.

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A uniform narrow tube 1.90 m long is open at both ends. It resonates at two successive harmonics of frequencies 280 Hz and 294 H
Over [174]

Answer:

a)14Hz

b)26.6m/s

Explanation:

a)we were given

the first harmonics frequencies as 280 Hz

The second harmonic frequency as 294 Hz.

The fundamental frequency is equal to the gap which means the distance that exist between the harmonics, then

the fundamental frequency=(294 - 280 = 10 Hz)

= 14Hz

b) We know the frequency and the wavelength of the sound wave (

We were told that the wavelength must be twice the length of the tube then, velocity can be calculated as

And fundamental frequency= 14Hz, and distance of 1.90 m then

v = f*2L = (14Hz)*2*(1.90 m) = 26.6m/s

Therefore, the speed of sound in the gas in the tubes is 26.6m/s

7 0
3 years ago
Determine the force the sun exerts on an object with a mass of 80.0 kg if that object is on the earth. What is the force exerted
MrRissso [65]

he has to read a tripple beam balence and mesure the pltates


3 0
3 years ago
Read 2 more answers
Freight trains can produce only relatively small acceleration and decelerations. (a) what is the final velocity (in m/s) of a fr
m_a_m_a [10]
(a) We will use the equation v = u + at
Initial velocity u = 5.00 m/s 
Acceleration a = 0.0600 m/s² 
time = 8 min = 8 x 60 = 480 s 
Final velocity 
= u + at 
= 5.00 + 0.0600(480) 
= 33.8 m/s

The final velocity is 33.8 m/s
5 0
3 years ago
Read 2 more answers
What is the process of preparing a person to perform strenuous work and to recover from that work as quickly as possible?
vesna_86 [32]
The process of preparing a person to perform strenuous work and to recover from that work as quickly as possible is called training, I bet. Such w<span>arm up exercises as  like stretching and other should lead person to the recovery. Hope it will help.</span>
3 0
4 years ago
Question 1
Agata [3.3K]

Answer:

Hypothesis:

The amount of limestone that dissolves in the acid is directly proportional to the concentration of acid used.

Explanation:

Acids dissolve limestone according to the following general equation;

2HX(aq) + CaCO3(s) -------> CaX2(aq) + H2O (l) + CO2(g). Where HX represents any acid at all.

This dissolution process is a chemical reaction. It was experimentally observed that the amount of limestone that dissolved in acid depends on the concentration of acid. Various concentrations of acid were then prepared and a particular mass of limestone was dissolved in each concentration of acid. The amount of limestone dissolved in each case was carefully noted.

It was observed that as the concentration of acid increased, the amount of limestone dissolved increased also and vice versa, hence the hypothesis proposed above.

3 0
4 years ago
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