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Volgvan
3 years ago
11

(1) Assume that the lights in your kitchen use 300 watts. How much energy (in kWh) does it use and how much does it cost to leav

e the lights on 24 hours a day for one year if electricity is 12cents/kilowatt hour
Physics
1 answer:
lbvjy [14]3 years ago
7 0

Answer:

the cost to leave the lights on 24 hours a day for one year is 31,536 cents or 315.36 dollars

Explanation:

Given that;

P = 300 watts = 300/1000 = 0.3

t = 24hrs a day

In a calendar year, we have 365 days

so;

E = 0.3 × 365 × 24

E = 2628 KWh

given that;  1 KWh = 12 cent

then 2628  KWh is x

x = 2628 × 12

x = 31,536 cents or 315.36 dollars

Therefore, the cost to leave the lights on 24 hours a day for one year is 31,536 cents or 315.36 dollars

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Two positive charged particles will ?
Vika [28.1K]

Answer:

make a negative

Explanation:

yep

6 0
3 years ago
Read 2 more answers
A transformer consisting of two coils wrapped around an iron core is connected to a generator and a resistor (Resistor is connec
V125BC [204]

Answer:

The peak emf of the generator is 40.94 V.

Explanation:

Given that,

Number of turns in primary coil= 11

Number of turns in secondary coil= 18

Peak voltage = 67 V

We nee to calculate the peak emf

Using relation of number of turns and emf

\dfrac{N_{1}}{N_{2}}=\dfrac{E_{1}}{E_{2}}

E_{1}=\dfrac{N_{1}}{N_{2}}\times E_{2}

Where, N₁ = Number of turns in primary coil

N₂ = Number of turns in secondary coil

E₂ = emf across secondary coil

Put the value into the formula

E_{1}=\dfrac{11}{18}\times67

E_{1}=40.94\ V

Hence, The peak emf of the generator is 40.94 V.

4 0
3 years ago
Is there a "real" simple machine that has an efficiency of 100%?
VARVARA [1.3K]

Answer:

NO

Explanation:

No, a machine cannot be 100% efficient. This is due to the movement of the moving parts siding against each other and causing friction. This friction is the one that creates heat and causes wear and tear between moving ports f the machine hence making the machine to decrease in efficiency with time

8 0
3 years ago
A car is moving in a straight line with the same speed of 100 m/s ,the acceleration in this
Amiraneli [1.4K]

Answer:

a = 0m/s²

Explanation:

Average acceleration = (change in velocity)/(time it takes). Since the car's change in velocity is zero, its acceleration is zero.

4 0
3 years ago
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
kati45 [8]

Answer:

The  coefficient of kinetic friction  \mu_k =  0.724

Explanation:

From the question we are told that

   The  length of the lane is  l =  36.0 \  m

    The speed of the truck is  v  =  22.6\  m/s

     

Generally from the work-energy theorem we have that  

    \Delta KE  =   N  *  \mu_k *  l

Here N  is the normal force acting on the truck which is mathematically represented as

     \Delta KE is the change in kinetic energy which is mathematically represented as

        \Delta KE =  \frac{1}{2} *  m *  v^2

=>     \Delta KE =  0.5  *  m *  22.6^2

=>      \Delta KE =  255.38m

        255.38m =    m *  9.8  *  \mu_k *   36.0

=>     255.38  =    352.8  *  \mu_k

=>   \mu_k =  0.724

 

6 0
3 years ago
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