1) 333.6 C
In order to have breakdown, the electric field at the surface of the cloud must be equal to the breakdown electric field:

The electric field strength at the surface of a charged sphere is given by

where
is the vacuum permittivity
Q is the charge on the sphere
R is the radius of the sphere
Here we have a cloud of radius

So we can re-arrange the previous equation in order to find the charge on the cloud:

2)
excess electrons
The total charge of the cloud must be (in magnitude)
Q = 333.3 C
We know that one electron carries a charge of

The total charge is just given by the charge of each electron multiplied by the number of excess electrons in the cloud:

where
N is the number of excess electrons
Solving for N, we find:

Answer:
<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:
a) V₀ = 23.4 m/s
b) h = 27.9 m
c) t = 0.96 s
d) t = 4.8 s
Explanation:
a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:

<u>Where:</u>
: is the final speed = 14 m/s
: is the initial speed =?
g: is the gravity = 9.81 m/s²
h: is the height = 18 m
b) The maximum height is:


c) The time can be found using the following equation:


d) The flight time is given by:

I hope it helps you!
Answer:
Sorry this isn’t going to be any help. You don’t have any statement that I’m able to see.
Explanation:
Answer:
<em>I = 0.75 Amp</em>
Explanation:
<u>Ohm's Law</u>
Ohm's law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points. The constant of proportionality is called the Resistance (R) of the conductor.
The formula can be expressed as:
V = I.R
The intensity of the current through a resistor can be calculated by solving the equation for I:

A flashlight bulb is an example of a resistor with the specific task to emit light when it's hot enough.
The potential difference (or voltage) is V=6 V and the resistance is R=8Ω, thus the current is:

I = 0.75 Amp