Ask question

Ask question

All categories

3 years ago

5

A sound wave is moving through air. The wave has a wavelength of 0.65 m and a frequency of 512 Hz. Calculate the speed of the wa

ve.

1 answer:

nexus9112 [7]3 years ago

6 0

Answer:

"332.8 m/s" is the right solution.

Explanation:

The given values are:

Wavelength,

$\lambda=0.65 \ m$

Frequency,

$f = 512 \ Hz$

As we know,

⇒ $Speed=Frequency\times Wavelength$

or,

⇒ $V=f\times \lambda$

By putting the given values in the above relation, we get

⇒ $=512\times 0.65$

⇒ $=332.8 \ m/s$

You might be interested in

Which time interval has the greatest speed?

shutvik [7]

Answer:

es la 2

Explanation:

epero que te curva

4 0

3 years ago

In a thunderstorm, electric charge builds up on the water droplets or ice crystals in a cloud. Thus, the charge can be considere

jolli1 [7]

1) 333.6 C

In order to have breakdown, the electric field at the surface of the cloud must be equal to the breakdown electric field:

$E=3.00\cdot 10^6 N/C$

The electric field strength at the surface of a charged sphere is given by

$E=\frac{1}{4\pi \epsilon_0} \frac{Q}{R^2}$

where

$\epsilon_0 = 8.85\cdot 10^{-12} C^2/(N^2 m^2)$ is the vacuum permittivity

Q is the charge on the sphere

R is the radius of the sphere

Here we have a cloud of radius

$R = 1.00 km = 1000 m$

So we can re-arrange the previous equation in order to find the charge on the cloud:

$Q=4\pi \epsilon_0 ER^2=4\pi (8.85\cdot 10^{-12})(3.00\cdot 10^6)(1000)^2=333.6 C$

2) $2.08\cdot 10^{21}$ excess electrons

The total charge of the cloud must be (in magnitude)

Q = 333.3 C

We know that one electron carries a charge of

$e = 1.6 \cdot 10^{-19}C$

The total charge is just given by the charge of each electron multiplied by the number of excess electrons in the cloud:

$Q=Ne$

where

N is the number of excess electrons

Solving for N, we find:

$N=\frac{Q}{e}=\frac{333.3 C}{1.6\cdot 10^{-19} C}=2.08\cdot 10^{21}$

6 0

3 years ago

(III) A baseball is seen to pass upward by a window with a vertical speed of If the ball was thrown by a person 18 m below on th

Ghella [55]

Answer:

<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:

a) V₀ = 23.4 m/s

b) h = 27.9 m

c) t = 0.96 s

d) t = 4.8 s

Explanation:

a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:

$V_{f}^{2} = V_{0}^{2} - 2gh$

<u>Where:</u>

$V_{f}$ : is the final speed = 14 m/s

$V_{0}$ : is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 18 m

$V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s$

b) The maximum height is:

$V_{f}^{2} = V_{0}^{2} - 2gh$

$h = \frac{V_{0}^{2}}{2g} = \frac{(23. 4 m/s)^{2}}{2*9.81 m/s^{2}} = 27.9 m$

c) The time can be found using the following equation:

$V_{f} = V_{0} - gt$

$t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s$

d) The flight time is given by:

$t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s$

I hope it helps you!

3 0

4 years ago

Which statement describes the effects of forces on an object

lukranit [14]

Answer:

Sorry this isn’t going to be any help. You don’t have any statement that I’m able to see.

Explanation:

8 0

3 years ago

a flashlight bulb with a potential difference of 6.0 v across it has a resistance of 8.0 how much current is the bulb filament

Andreas93 [3]

Answer:

<em>I = 0.75 Amp</em>

Explanation:

<u>Ohm's Law</u>

Ohm's law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points. The constant of proportionality is called the Resistance (R) of the conductor.

The formula can be expressed as:

V = I.R

The intensity of the current through a resistor can be calculated by solving the equation for I:

$\displaystyle I=\frac{V}{R}$

A flashlight bulb is an example of a resistor with the specific task to emit light when it's hot enough.

The potential difference (or voltage) is V=6 V and the resistance is R=8Ω, thus the current is:

$\displaystyle I=\frac{6~V}{8~\Omega}$

I = 0.75 Amp

3 0

3 years ago