Answer:
3rd one
Explanation:
they are pointing right 2 left because most things start at the right in which even if the force of both direction is the same, it acquires more force. i learned this from my science teacher yesterday in Zoom
One of the major limitations of using the ball and stick model for DNA, is that within a single double stranded segment of DNA, one would have to use many many balls to represent atoms that are present in the sugar phosphate backbone, along with all of the main atoms that compose the nitrogenous bases of DNA, we also cannot construct or show the helical form of DNA, by using balls and sticks as well.
Answer:
Sodium Bromide + Dichlorine = Sodium Chloride + Dibromine
Reaction Type
Single Displacement (Substitution)
Explanation:
Explanation:
a) The height of the ball h with respect to the reference line is
![h = L - L\cos{31°} = L(1 - \cos{31°})](https://tex.z-dn.net/?f=h%20%3D%20L%20-%20L%5Ccos%7B31%C2%B0%7D%20%3D%20L%281%20-%20%5Ccos%7B31%C2%B0%7D%29)
so its initial gravitational potential energy
is
![U = mgh = mgL(1 - \cos{31°})](https://tex.z-dn.net/?f=U%20%3D%20mgh%20%3D%20mgL%281%20-%20%5Ccos%7B31%C2%B0%7D%29)
![\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%3D%280.25%5C%3A%5Ctext%7Bkg%7D%29%289.8%5C%3A%5Ctext%7Bm%2Fs%7D%5E2%29%280.65%5C%3A%5Ctext%7Bm%7D%29%281%20-%20%5Ccos%7B31%7D%29)
![\:\:\:\:\:=0.23\:\text{J}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%3D0.23%5C%3A%5Ctext%7BJ%7D)
b) To find the speed of the ball at the reference point, let's use the conservation law of energy:
![\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U](https://tex.z-dn.net/?f=%5CDelta%7BK%7D%20%2B%20%5CDelta%7BU%7D%20%3D%200%20%5CRightarrow%20K_0%20%2B%20U_0%20%3D%20K%20%2B%20U)
We know that the initial kinetic energy
as well as its final gravitational potential energy
are zero so we can write the conservation law as
![mgL(1 - \cos{31°}) = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=mgL%281%20-%20%5Ccos%7B31%C2%B0%7D%29%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
Note that the mass gets cancelled out and then we solve for the velocity v as
![v = \sqrt{2gL(1 - \cos{31°})}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2gL%281%20-%20%5Ccos%7B31%C2%B0%7D%29%7D)
![\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%3D%20%5Csqrt%7B2%289.8%5C%3A%5Ctext%7Bm%2Fs%7D%5E2%29%280.65%5C%3A%5Ctext%7Bm%7D%29%281%20-%20%5Ccos%7B31%C2%B0%7D%29%7D)
![\:\:\:\:\:= 1.3\:\text{m/s}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%3D%201.3%5C%3A%5Ctext%7Bm%2Fs%7D)
Answer:
70.5 mph
Explanation:
A passenger jet travels from Los Angeles to Bombay, India, in 22h.
The return flight takes 17 h.
The difference in flight times is caused by winds over the Pacific Ocean that
blow primarily from west to east.
If the jet's average speed in still air is 550 mi/h what is the average speed
of the wind during the round trip flight? Round to the nearest mile per hour.
Is your answer reasonable?
:
Let w = speed of the wind
:
Write a distance equation (dist is the same both ways
17(550+w) = 22(550-w)
9350 + 17w = 12100 - 22w
17w + 22w = 12100 - 9350
39w = 2750
W = 2750/39
w = 70.5 mph seems very reasonable
:
Confirming if the solution by finding the distances using these value
17(550+70.5) = 10549 mi
22(550-70.5) = 10549 mi; confirms our solution of w = 70.5 mph