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choli [55]
2 years ago
11

How many grams are in 6.53 moles of Mn?

Physics
1 answer:
Westkost [7]2 years ago
3 0

Answer:

359 g Mn

General Formulas and Concepts:

  • Dimensional Analysis
  • Reading the Periodic Table of Elements

Explanation:

<u>Step 1: Define</u>

6.53 mol Mn

<u>Step 2: Find conversion</u>

1 mol Mn = 54.94 g Mn

<u>Step 3: Dimensional Analysis</u>

<u />6.53 \hspace{3} mol \hspace{3} Mn(\frac{54.94 \hspace{3} g \hspace{3} Mn}{1 \hspace{3} mol \hspace{3} Mn} ) = 358.758 g Mn

<u>Step 4: Simplify</u>

<em>We are given 3 sig figs.</em>

358.758 g Mn ≈ 359 g Mn

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Answer:

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Explanation:

As this gas is cooled at constant temperature of 320 K, this means that we are on an isothermal process, and according to the 1st law of thermodynamics:

Q = W   (1)

And as the temperature is constant, we can use the following expression to calculate the Work done:

W = nRT ln(V₁/V₂)   (2)

However, as Q = W, we can replace heat into the above expression and then solve for V₂:

Q = nRT ln(V₁/V₂)

Replacing we have:

1200 = (1.5 * 8.314 * 320) ln(19/V₂)

1200 = 39907.2 ln(19/V₂)

ln(19/V₂) = 1200/3990.72

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Hope this helps

6 0
3 years ago
Sharks are generally negatively buoyant; the upward buoyant force is less than the weight force. This is one reason sharks tend
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Answer:

8.67807 N

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Explanation:

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\rho_{sh} = Density of shark = 1040 kg/m³

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Net force on the fin is (seawater)

F_n=mg-V_s\rho_{se}g\\\Rightarrow F_n=mg-\frac{m}{\rho_{sh}}\rho_{se}g\\\Rightarrow F_n=92\times 9.81-\frac{92}{1040}\times 1030\times 9.81\\\Rightarrow F_n=8.67807\ N

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Net force on the fin is (freshwater)

F_n=mg-V_s\rho_{f}g\\\Rightarrow F_n=mg-\frac{m}{\rho_{sh}}\rho_{f}g\\\Rightarrow F_n=92\times 9.81-\frac{92}{1040}\times 1000\times 9.81\\\Rightarrow F_n=34.7123\ N

The lift force required in a river is 34.7123 N

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3 years ago
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Answer:

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Explanation:

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(5+0.18, 2-0.1)

= ( 5.18, 1.9)

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3 years ago
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Potassium-A
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