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gladu [14]
3 years ago
7

Rocks are elastic too! Explain how elasticity and Harry Reid's elastic rebound theory lead to a better understanding of earthqua

kes.
Physics
1 answer:
ANEK [815]3 years ago
7 0
After the great 1906 San Francisco earthquake, geolophysicistHarry Fielding Reid examined the displacement of the ground surface along the San Andreas Fault. He concluded that the quake must have been the result of the elastic reboundof the strain energy in the rocks on either side of the fault.
strain energy is 0. 5x force x (compression) X (compression)
There is a lot of force and a bit of compression when rocks squash up against other rocks causing earthquakes
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An electric toy with a resistance of 2.50 Ω is operated by a 3.00-V battery. (a) What current does the toy draw? (b) Assuming th
Leno4ka [110]

Answer:

a) The current is i = 1.2 A

b) The charge is Q = 17280 C

c) The energy is E = 43200 J

Explanation:

a) The current is given by the ohm's law wich is:

i = V/R = 3/2.5 = 1.2 A

b) Since the charge is steady we can use the following equation to find the charge amount in that time:

i = Q/t

Q = t*i

Where t is in seconds, so we have 4h * 3600 = 14400 s

Q = 1.2*14400 = 17280 C

c)  The energy is the power delivered to the toy multiplied by the time:

P = 1.2*2.5 = 3 W

E = P*t = 3*14400 = 43200 J

7 0
3 years ago
A car of mass 600kg is moving at 15m/s. The driver accelerate gently to a final velocity of 30m/s so that a force of force acts
Anvisha [2.4K]

Answer:

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3 0
3 years ago
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Which materials are made of one kind of atom
kirill115 [55]
Elements are pure substances that are composed or made out of only 1 kind of atom.
3 0
3 years ago
If the Moon rises at 7 A.M. on a particular day, then approximately what time will it rise four days later?
Gelneren [198K]

Answer:

10:33 am

Explanation:

3 0
3 years ago
A 108 kg clock initially at rest on a horizontal floor requires a 653 N horizontal force to set it in motion. After the clock is
kifflom [539]

Answer:

\mu_s=0.61

\mu_k=0.49

Explanation:

Given that,

Mass of the clock, m = 108 kg

When the clock is not moving, force acting on it, F_1=653\ N

For the clock in motion, force acting on it, F_2=527\ N

To find,

\mu_s\ and\ \mu_k

Solution,

When an object is at rest, the force acting on it is called force due to static friction and if the object is in motion, the force acting on its called force due to kinetic friction.

Let \mu_s is the coefficient of static friction. Force is given by :

F_s=\mu_smg

\mu_s=\dfrac{F_s}{mg}

\mu_s=\dfrac{653}{108\times 9.8}

\mu_s=0.61

Let  \mu_k is the coefficient of kinetic friction. Force is given by :

F_k=\mu_kmg

\mu_k=\dfrac{F_k}{mg}

\mu_k=\dfrac{527}{108\times 9.8}

\mu_k=0.49

8 0
3 years ago
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