The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial 
has solutions 
, then you can factor it as
So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as
But this is a fourth-degree polynomial.
Answer:
17
Step-by-step explanation:
Answer:
n ≥ -4
Step-by-step explanation:
-3/4n ≤ 3
-4/3(-3/4n) ≤ 3(-4/3)
n ≥ -12/3
n ≥ -4
CHECK:
correct
-3/4(-4) ≤ 3
12/4 ≤ 3
3 = 3
correct
-3/4(5) ≤ 3
-15/4 ≤ 3
-3.75 < 3
incorrect
-3/4(1) ≤ 3
-3/4 is not ≤ 3
Answer:3rd option
Step-by-step explanation:
tan(R) = 7/4
Thus, the angle measure of R is the inverse tan of 7/4, or the 3rd option. Just define what tan(R) is, and then solve.
Answer:
7% interest = $10000
13% interest = $20000
Step-by-step explanation:
Let the amount invested at 7% interest be x.
Let the amount invested at 13% interest be y.
Thus;
x + y = 30000 - - - (eq 1)
We want to find out how much Paul needs to invest in each option to make a total 11% return on his $30,000.
Thus;
0.07x + 0.13y = 0.11(30000)
Multiply through by 100 to get rid of the decimal;
7x + 13y = 0.11(30000 × 100).
7x + 13y = 330000 - - - (eq 2)
From eq 1, x = 30000 - y
Put this for x in eq 2 to get;
7(30000 - y) + 13y = 330000
210000 - 7y + 13y = 330000
6y = 330000 - 210000
6y = 120000
y = 120000/6
y = $20000
x = 30000 - 20000
x = $10000
Thus;
Amount invested at;
7% interest = $10000
13% interest = $20000
