In order to compute the total hydrogen atoms present, we must first write the molecular formulas of ammonia and water to know how many hydrogen atoms are present in each molecule.
Water - H₂O; so 2 hydrogen atoms per molecule of water
Ammonia - NH₃; so 3 hydrogen atoms per molecule of ammonia
Total hydrogen atoms = 2 * molecules of water + 3 * molecules of ammonia
H atoms = 2 * 1.5 x 10²⁵ + 3 * 8.2 x 10²⁴
H atoms = 5.46 x 10²⁵
There are a total of 5.46 x 10²⁵ hydrogen atoms in the solution
Answer:
0.06mole
Explanation:
Given parameters:
Volume of balloon = 2.5L
T = 343.5K
P = 66.7kPa; in atm gives = 0.66atm
Unknown:
Number of moles of He = ?
Solution:
To solve this problem, we use the ideal gas equation.
It is mathematically expressed as;
Pv = nRT
where p is the pressure
v is the volume
n is the number of moles
R is the gas constant
T is the temperature
0.66 x 2.5 = n x 0.082 x 343.5
n = 0.06mole
The number of years required for 1/4 cobalt-60 to remain after decay is calculated as follows
after one half life 1/2 of the original mass isotope remains
after another half life 1/4 mass of original mass remains
therefore if one half life is 5.3 years then the years required
= 2 x 5.3years = 10.6 years
Answer:
0.4951 grams of Zn have been consumed.
Explanation:
Pressure at which gas is collected over water = p = 732 Torr
Vapor pressure of the water = p' = 26.74 Torr
Pressure of hydrogen gas = P
p = P + p'
P = p - p' = 732 Torr - 26.74 Torr = 705.26Torr
P =
1 atm = 760 Torr
Volume of the hydrogen gas = V = 201 mL = 0.201 L
1 mL= 0.001 L
Moles of hydrogen gas = n
Temperature at which hydrogen gas collected = T = 27°C = 27+273 K = 300 K
Using an ideal gas equation:
n = 0.007573 mol
According to recation , 1 mole of hydrgen gas was obtained from 1 mole of zinc,then 0.007573 moles of hydrgen gas will be obtained from;
of zinc
Mass of 0.007573 moles of zinc:
0.007573 mol × 65.38 g/mol = 0.4951 g
0.4951 grams of Zn have been consumed.
You can use the formula M1 x V1 = M2 x V2 where M1 is the molarity of the first substance and V1 is the volume of the substance. M2 is the molarity of the 2nd substance and V2 is the volume of the substance
if substance 1 is HCl and 2 is KOH we can set up the following equation
x moles / liter (unknown) x .02 liters = .5 moles/ liter x .032 liters
x moles / liter x .02 liters = .016 moles
x moles / liter = .016/.02 liters
x moles / liter = .8 moles/ liter
You have . 8M HCL