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3 years ago

Does the antifreeze you put in a car radiator have a lower or higher freezing point than water

1 answer:

7 0

Hello!
Antifreeze says it in the name. This means that it helps prevent freezing. The liquid that would freeze if you wouldnt use the antifreeze is water. This means that the antifreeze has to have a higher freezing point then water, because otherwise it would only freeze faster!

Hope this helped you!

You might be interested in

Name the element found in a water molecule.

skelet666 [1.2K]

Answer:

Oxygen atom

Explanation:

A water molecule consists of three atoms; an oxygen atom and two hydrogen atoms, which are bond together like little magnets. The atoms consist of matter that has a nucleus in the centre.

5 0

3 years ago

Read 2 more answers

Question 6

kompoz [17]

Considering the combined law equation, the new temperature is -244.56 °C or 28.44 K.

<h3>Boyle's law</h3>

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.

Mathematically, this law states that the multiplication of pressure by volume is constant:

P×V=k

<h3>Charles's law</h3>

Charles's law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles' law states that the ratio of volume to temperature is constant:

$\frac{V}{T} =k$

<h3>Gay-Lussac's law </h3>

Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: increasing the temperature will increase the pressure, while decreasing the temperature will decrease the pressure.

Mathematically, Gay-Lussac's law states that the ratio of pressure to temperature is constant:

$\frac{P}{T} =k$

<h3>Combined law equation</h3>

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{PxV}{T} =k$

Considering an initial state 1 and a final state 2, it is fulfilled:

$\frac{P1xV1}{T1} =\frac{P2xV2}{T2}$

<h3>New temperature</h3>

In this case, you know:

P1= 1 atm= 760 mmHg
V1= 15 L
T1= -30 °C= 243 K (being 0 °C= 273 K)
P2= 58 mmHg
V2= 23 L
T2= ?

Replacing in the combined law equation:

$\frac{760 mmHgx15 L}{243 K} =\frac{58 mmHgx23 L}{T2}$

Solving:

$T2x\frac{760 mmHgx15 L}{243 K} =58 mmHgx23 L$

$T2 =\frac{58 mmHgx23 L}{\frac{760 mmHgx15 L}{243 K}}$

Finally, the new temperature is -244.56 °C or 28.44 K.

Learn more about combined law equation:

brainly.com/question/4147359

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6 0

1 year ago

Explain the relationship between heat transfer and calorimetry. Justify your response in two or more complete sentences.

babymother [125]

Calorimetry is the measurement of the quantity of heat in a substance. It is a method that is used to measure the energy content of food. It is also used to measure the specific heat of substances.

8 0

3 years ago

Match the correct type of energy transfer that takes place.

icang [17]

Answer:

Lightbulb: electrical energy to light energy

Alarm Clock: electrical energy to sound energy

Rollercoaster: electrical energy to mechanical energy

Riding a Bike: chemical energy to mechanical energy

Explanation:

Light bulbs, alarm clocks, and roller coasters require electrical energy to work. This energy then changes into the subsequent types. Light bulbs primarily emit that energy in the form of light, alarm clocks change that energy into sound, and roller coasters begin to move (mechanical). People power bikes, and the energy in our body is stored as chemical energy. So, when we rides bikes, that energy gets turned into moving (mechanical) energy.

7 0

2 years ago

Calculate the work (w) and ΔEo, in kJ, at 298 K and 1 atm pressure, for the combustion of one mole of C4H10 (g). First write and

Paul [167]

Answer:

Explanation:

2C₄H₁₀ + 13O₂ = 8 CO₂ + 10H₂O

Change in number of moles Δn = 18 - 15 = + 3 moles .

ΔHo = -2658.3 kJ/mol.

ΔHo = ΔEo+ Δn RT

Δn = 3

For one mole Δn = 1.5

ΔHo = ΔEo+ W

W = Δn RT

= 1.5 x 8.31 x 298

= 3714.5 J

= 3.7 kJ /mole

ΔHo = ΔEo+ W

ΔEo = ΔHo - W

= -2658.3 - 3.7 kJ

= - 2662 kJ .

3 0

3 years ago