Answer:
Mg donates two electrons to O
Explanation:
Lewis dot notation uses dots and crosses to represent valence electrons on atoms.
Magnesium is a metal and would donate or lose electrons during bonding.
Oxygen is a non metal and would gain electrons during bonding.
The correct option is;
Mg donates two electrons to O
Attractive antennas that pull the waves tword it.
Answer:
9) Substitution Reaction
10) Covalent Bond
11) Ionic Bond
12) Covalent Bond
13) Ionic Bond
14) 9 atoms
Explanation:
9) Substitution Reaction: Substitution reaction is a chemical reaction in which one atom, ion or species replaced by another atom, ion or species
10) Covalent Bond: Covalent bond is a bond that formed between two nonmetals, when both the species are non metal, the electronegativity of both the nonmetals are comparatively same, hence any of both do not pulls completely electron of other & the bond is formed by the sharing of electron.
11) Ionic Bond: We know that nonmetals have high electronegativity than those of metals, due to high electronegativity non metals pulls the electrons of metals but there is enough interaction that non metal do not escape after pulling the electron, & an ionic bond generates where non metals possess negative charge & positive charge goes to metal.
12) Covalent Bond: The bond formed between two atoms having less electronegativity diffrence by sharing of electron pair is know as covalent bond. for e.g the Carbon - Hydrogen bond in methane (CH4) molecule is covalent bonded because the electronegativity of carbon is 2.5 & that of hydrogen is 2.1 which is almost close, hence the bond formed is covalent.
13) Ionic Bond: The bond formed between two atoms having high electronegativity diffrence & the bond formed is due to complete transfer of electron by one species. For e.g. NaCl the sodium is a metal having electronegativity 0.9 and chlorine is non metal having electronegativity 3.0 the electronegativity diffrence is too high, hence the chlorine behaves as Cl- ion that of sodium as Na+, both the components behaves as ion but they are bonded &that bond is called as Ionic bond.
14) 9 Atoms: One molecule of water (H2O) posses three atoms, two hydrogen atoms & one oxygen atom, the number of atoms in 3 molecules of water 3×3 = 9 atoms.
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Answer:
There is 37.36 grams of K3PO4 produced
Explanation:
Step 1: Data given
Mass of H3PO4 = 29.6 grams
KOH is in excess
Molar mass of KOH = 56.11 g/mol
Molar mass of H3PO4 = 97.99 g/mol
Step 2: The balanced equation
3KOH(aq) + H3PO4(aq) ⇔ K3PO4(aq)+3H2O(l)
Step 3: Calculate mass of KOH
Mass KOH = mass KOH / molar mass KOH
Mass KOH = 29.6 grams / 56.11 g/mol
Mass KOH = 0.528 moles
Step 4: Calculate moles of K3PO4
Since KOH is the limiting reactant, We need 3 moles of KOH for each moles of H3PO4, to produce 1 mole of K3PO4 and 3 moles of H2O
For 0.528 moles of KOH we'll have 0.528/3 = 0.176 moles of K3PO4
Step 5: Calculate mass of K3PO4
Mass K3PO4 = moles K3PO4 * molar mass K3PO4
Mass K3PO4 = 0.176 moles * 212.27 g/mol
Mass K3PO4 = 37.36 grams
There is 37.36 grams of K3PO4 produced
The given question is incomplete. The complete question is as follows.
Sodium sulfate is slowly added to a solution containing 0.0500 M
and 0.0390 M
. What will be the concentration of
(aq) when
begins to precipitate? What percentage of the
can be separated from the Ag(aq) by selective precipitation?
Explanation:
The given reaction is as follows.

= 0.0390 M
When
precipitates then expression for
will be as follows.
![K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5E%7B2%7D%5BSO%5E%7B2-%7D_%7B4%7D%5D)
![1.20 \times 10^{-5} = (0.0390)^{2} \times [SO^{2-}_{4}]](https://tex.z-dn.net/?f=1.20%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20%280.0390%29%5E%7B2%7D%20%5Ctimes%20%5BSO%5E%7B2-%7D_%7B4%7D%5D)
= 0.00788 M
Now, equation for dissociation of calcium sulfate is as follows.

![K_{sp} = [Ca^{2+}][SO^{2-}_{4}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCa%5E%7B2%2B%7D%5D%5BSO%5E%7B2-%7D_%7B4%7D%5D)
![4.93 \times 10^{-5} = [Ca^{2+}] \times 0.00788](https://tex.z-dn.net/?f=4.93%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20%5BCa%5E%7B2%2B%7D%5D%20%5Ctimes%200.00788)
= 0.00625 M
Now, we will calculate the percentage of
remaining in the solution as follows.

= 12.5%
And, the percentage of
that can be separated is as follows.
100 - 12.5
= 87.5%
Thus, we can conclude that 87.5% will be the concentration of
when
begins to precipitate.