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coldgirl [10]
3 years ago
8

g If you have three identical containers (same volume) at the same temperature and pressure, each with a different gas. Containe

r A has He, container B has Ne, and container C has O2. Which flask contains the largest number of molecules? Group of answer choices
Chemistry
1 answer:
vekshin13 years ago
6 0

Answer:

<em>The three gases, in the three identical containers, will all have the same number of molecules</em>

Explanation:

If these three gases (Helium He, Neon Ne, and Oxygen O_{2}) are all contained in separate identical containers with the same volume. And they are all stored at the same temperature, and pressure. Then, they'll all contain the same number of molecules. This is in line with Avogadro's law which states that "Equal volume of all gases, at the same temperature and pressure, have the same number of molecules."

You might be interested in
The Lewis dot notation for two atoms is shown.
Iteru [2.4K]

Answer:

Mg donates two electrons to O

Explanation:

Lewis dot notation uses dots and crosses to represent valence electrons on atoms.

Magnesium is a metal and would donate or lose electrons during bonding.

Oxygen is a non metal and would gain electrons during bonding.

The correct option is;

Mg donates two electrons to O

5 0
3 years ago
How are radio waves transmitted
kotegsom [21]
Attractive antennas that pull the waves tword it.
7 0
3 years ago
Can someone help me with these questions?
Gennadij [26K]

Answer:

9) Substitution Reaction

10) Covalent Bond

11) Ionic Bond

12) Covalent Bond

13) Ionic Bond

14) 9 atoms

Explanation:

9) Substitution Reaction: Substitution reaction is a chemical reaction in which one atom, ion or species replaced by another atom, ion or species

10) Covalent Bond: Covalent bond is a bond that formed between two nonmetals, when both the species are non metal, the electronegativity of both the nonmetals are comparatively same, hence any of both do not pulls completely electron of other & the bond is formed by the sharing of electron.

11) Ionic Bond: We know that nonmetals have high electronegativity than those of metals, due to high electronegativity non metals pulls the electrons of metals but there is enough interaction that non metal do not escape after pulling the electron, & an ionic bond generates where non metals possess negative charge & positive charge goes to metal.

12) Covalent Bond: The bond formed between two atoms having less electronegativity diffrence by sharing of electron pair is know as covalent bond. for e.g the Carbon - Hydrogen bond in methane (CH4) molecule is covalent bonded because the electronegativity of carbon is 2.5 & that of hydrogen is 2.1 which is almost close, hence the bond formed is covalent.

13) Ionic Bond: The bond formed between two atoms having high electronegativity diffrence & the bond formed is due to complete transfer of electron by one species. For e.g. NaCl the sodium is a metal having electronegativity 0.9 and chlorine is non metal having electronegativity 3.0 the electronegativity diffrence is too high, hence the chlorine behaves as Cl- ion that of sodium as Na+, both the components behaves as ion but they are bonded &that bond is called as Ionic bond.

14) 9 Atoms: One molecule of water (H2O) posses three atoms, two hydrogen atoms & one oxygen atom, the number of atoms in 3 molecules of water 3×3 = 9 atoms.

<em><u>Thanks for joining brainly community!</u></em>

3 0
2 years ago
According to the following reaction, how many grams of potassium phosphate will be formed upon the complete reaction of 29.6 gra
Ugo [173]

Answer:

There is 37.36 grams of K3PO4 produced

Explanation:

Step 1: Data given

Mass of H3PO4 = 29.6 grams

KOH is in excess

Molar mass of KOH = 56.11 g/mol

Molar mass of H3PO4 = 97.99 g/mol

Step 2: The balanced equation

3KOH(aq) + H3PO4(aq) ⇔ K3PO4(aq)+3H2O(l)

Step 3: Calculate mass of KOH

Mass KOH = mass KOH / molar mass KOH

Mass KOH = 29.6 grams / 56.11 g/mol

Mass KOH = 0.528 moles

Step 4: Calculate moles of K3PO4

Since KOH is the limiting reactant, We need 3 moles of KOH for each moles of H3PO4, to produce 1 mole of K3PO4 and 3 moles of H2O

For 0.528 moles of KOH we'll have 0.528/3 =  0.176 moles of K3PO4

Step 5: Calculate mass of K3PO4

Mass K3PO4 = moles K3PO4 * molar mass K3PO4

Mass K3PO4 = 0.176 moles * 212.27 g/mol

Mass K3PO4 = 37.36 grams

There is 37.36 grams of K3PO4 produced

8 0
3 years ago
Sodium sulfate is slowly added to a solution containing 0.0500 M Ca 2 + ( aq ) and 0.0390 M Ag + ( aq ) . What will be the conce
levacccp [35]

The given question is incomplete. The complete question is as follows.

Sodium sulfate is slowly added to a solution containing 0.0500 M Ca^{2+}(aq) and 0.0390 M Ag^{+}(aq). What will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate? What percentage of the Ca^{2+}(aq) can be separated from the Ag(aq) by selective precipitation?

Explanation:

The given reaction is as follows.

      Ag_{2}SO_{4} \rightleftharpoons 2Ag^{+} + SO^{2-}_{4}

[Ag^{+}] = 0.0390 M

When Ag_{2}SO_{4} precipitates then expression for K_{sp} will be as follows.

         K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]

        1.20 \times 10^{-5} = (0.0390)^{2} \times [SO^{2-}_{4}]

       [SO^{2-}_{4}] = 0.00788 M

Now, equation for dissociation of calcium sulfate is as follows.

         CaSO_{4} \rightleftharpoons Ca^{2+} + SO^{2-}_{4}

      K_{sp} = [Ca^{2+}][SO^{2-}_{4}]

     4.93 \times 10^{-5} = [Ca^{2+}] \times 0.00788

           [Ca^{2+}] = 0.00625 M

Now, we will calculate the percentage of Ca^{2+} remaining in the solution as follows.

               \frac{0.00625}{0.05} \times 100

                 = 12.5%

And, the percentage of Ca^{2+} that can be separated is as follows.

                     100 - 12.5

                     = 87.5%

Thus, we can conclude that 87.5% will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate.

4 0
3 years ago
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