Answer:
0.047 %
Explanation:
Step 1: Given data
- Partial pressure of ozone (pO₃): 0.33 torr
- Total pressure of air (P): 695 torr
Step 2: Calculate the %v/v of ozone in the air
Air is a mixture of gases. We can find the %v/v of ozone (a component) in the air (mixture) using the following expression.
<em>%v/v = pO₃/P × 100%</em>
%v/v = 0.33 torr/695 torr × 100%
%v/v = 0.047 %
<span>a) movement of heat through space </span>
<span>LiOH+HBr---> LiBr +h20. Moles of LiOH = 10/24 = 0.41moles. According to stoichiometry, moles of LiOH = moles of LiBr = 0.41moles. Therefore mass of LiBr =moles of LiBr x molecular weight of LiBr = o.41 x 87 = 35.67g. Hope it helps </span>
Answer: It's 2:2
Explanation: you can look at the coefficient stands in front of the chemical
For example if they ask the ratio of oxygen to sulfur trioxide, it would be 3:2 and vice versa vv..
I can’t answer the exact thing, but I know how to do it. One of the nitrogen bases always pairs with a different one, so once you know what pairs with what you just write it down. If you need more help just ask :) tip: one base will only join with a different one. One won’t join to multiple (from what I know as of now)
