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2 years ago

Calculate the ΔG for the following system. Then state if the system is spontaneous or not spontaneous.

Chemistry

2 answers:

skad [1K]2 years ago

5 0

+25 kJ; not spontaneous is your answer :) Hope this helps.

Leokris [45]2 years ago

4 0

Answer:

The correct answer is option B.

Explanation:

Enthalpy of the system = $\Delta H=+25 kJ=25,000 J$

Entropy of the system = $\Delta S=+5.0 J/K$

Temperature of the system =T =23°C = 296 K

The Gibbs's free energy is given by;

$\Delta G=\Delta H-T\Delta S$

$\Delta G=25,000 J-296 K\times 5.0 J/K =23,520 J=23.5 kJ$

The value of ΔG is positive which means that system is not spontaneous.

Hence, from the given options the most closest value to our answer is option B.

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2 years ago

You have at your disposal 3 1-pound bags of various pure salts that dissolve readily in water. You can add one of the bags to a

Sedaia [141]

Answer:

This question appears incomplete

Explanation:

However, it should be noted that addition of soluble salts generally lowers the freezing point of water hence after the addition, water will no longer freeze at 0°C but lower.

Soluble salts tend to form more ions in water, it is these ions that are responsible for interfering with the hydrogen bonds hence lowering the freezing. Thus, (since each bag are of the same weight) <u>the bag that contains the salt that ionizes more in water will lower the freezing point by the greatest amount</u>.

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6 0

3 years ago

A tetraphenyl phosphonium chloride (TPPCl) powder (FW=342.39) is 94.0 percent pure. How many grams are needed to prepare 0.45 L

slega [8]

Answer:

5.41 g

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For tetraphenyl phosphonium chloride :

Molarity = 33.0 mM = 0.033 M (As, 1 mM = 0.001 M)

Volume = 0.45 L

Thus, moles of tetraphenyl phosphonium chloride :

$Moles=0.033 \times {0.45}\ moles$

Moles of TPPCl = 0.01485 moles

Molar mass of TPPCl = 342.39 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.01485\ g= \frac{Mass}{342.39\ g/mol}$

Mass of TPPCl = 5.0845 g

Also,

TPPCl is 94.0 % pure.

It means that 94.0 g is present in 100 g of powder

5.0845 g is present in 5.41 g of the powder.

<u>Answer - 5.41 g</u>

5 0

3 years ago