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Anestetic [448]
3 years ago
12

Find the area of these figures

Mathematics
1 answer:
djyliett [7]3 years ago
3 0

Answer:

I think the answer for the first one would be 32^2 meters for 4m × 4m and 13m. The 6m and 8m would be 48^2 meters. The second one would be 5in × 5in would be 25in and 2in × 4in would be 8in. The third one would be 6ft × 6ft × 6ft would be 48ft.

Step-by-step explanation:

To find area, you have to multiply the sides of each figure.

  1. A = a^2 = 4m × 4m × 13m = 32.
  2. A = a^2 = 6m × 8m = 48.
  3. 5 × 5 = 25.
  4. 2 × 4 = 8.
  5. 6 × 6 = 36 + 12 = 48.

I hope this helps your question!

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6) A sample of water is being cooled according to the formula is given by
Vinvika [58]

Answer:

Relevant domain: [0 40]

Relevant range: [0 80]

Step-by-step explanation:

We have the following function:

C(t) = 80 - 2t

In which C(t) is the water temperature.

t is the time.

The colling period ends when the water freezes (0°).

So it freezes after t minutes, and t is found when C(t) = 0. So

C(t) = 80 - 2t

80 - 2t = 0

2t = 80

t = \frac{80}{2}

t = 40

Relevant domain:

Input value of the function, which is in minutes. So between 0(initial) and 40(when the water freezes).

Relevant range:

Initial temperature, which is C(0) = 80, until it freezes, 0. So from 0 to 80.

5 0
3 years ago
Find the slope between the two points (6,8)<br> (10,11)<br> -3/4<br> 3/4<br> 19/16<br> 4/3
Kazeer [188]

Answer:

Slope = \frac{3}{4}

Step-by-step explanation:

(x₁ , y₁) = (6 , 8)   &  (x₂ , y₂) = (10 , 11)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\

        = \frac{11-8}{10-6}\\\\=\frac{3}{4}

5 0
3 years ago
Find the value of x in the shown figure
zhannawk [14.2K]
Im not really sure if im right but i think the answer is 140-

Explanation:
I added 30+10 which equalled 40 and then i noticed the circle which would equal 360 and subtracted it from the 40 however that got me more then i needed since it wasnt one of the choices. Then i thought hmm maybe its a supplementary angle which usually equals 180 so i subtracted it from 40 which got me 140! Like i said i dont know if im right or not :(
3 0
3 years ago
This graph looks like a trigonometric function. Which trigonometric function would be best to use for this model: cosine, sine,
Trava [24]
Sine wave with amplitude 0.25
Period is 4/3
h(t) = 0.25Sin((2Pi/4/3)t) = 0.25Sin((3Pi/2)t)
5 0
4 years ago
The length of a rectangle is 5 times it’s width. If the perimeter of a rectangle is 72 m, find its area
Olenka [21]
X = width. the perimeter of a rectangle is 2*length + 2*width, so the perimeter of this rectangle is 2x + 2(5x) = 72. distribute the two to get 2x + 10x = 72. so 12x = 72. divide by twelve to get x = 6. the width is six, so the perimeter (5x) is 30. the area of a rectangle is length times width, 30*6, so the area is 180 m.
6 0
4 years ago
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