Question

Please help I will brainliest!! Really urgent!!

Answer 1

Answer:

$\frac{5}{6}$x-10

Step-by-step explanation:

($\frac{1}{3}$x-8)+($\frac{1}{2}$x-2) = $\frac{1}{3}$x-8+$\frac{1}{2}$x-2

$\frac{1}{3}$x-8+$\frac{1}{2}$x-2 = $\frac{1}{3}$x+$\frac{1}{2}$x-10

If you -8 then -2, you are subtracting 10 from the equation in total.

$\frac{1}{3}$x+$\frac{1}{2}$x-10 = $\frac{2}{6}$x+$\frac{3}{6}$x-10

To make the denominator the same, I will multiply the first fraction by 2 and the second fraction by 3 so that their denominators are 6.

$\frac{2}{6}$x+$\frac{3}{6}$x-10 = $\frac{5}{6}$x-10

Once the denominators are the same, you can do the working for the numerators directly (2+3=5) and keep the denominator the same.

Answer 2

Answer:    $\frac{5}{6}x-10$

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Work Shown:

$\left(\frac{1}{3}x-8\right)+\left(\frac{1}{2}x-2\right)\\\\\frac{1}{3}x-8+\frac{1}{2}x-2\\\\\left(\frac{1}{3}x+\frac{1}{2}x\right)+(-8-2)\\\\\left(\frac{1}{3}+\frac{1}{2}\right)x-10\\\\\left(\frac{2}{6}+\frac{3}{6}\right)x-10\\\\\frac{2+3}{6}x-10\\\\\frac{5}{6}x-10$