Please help me please

VMariaS [17]

Check the picture below.

well, since the triangle is an isosceles, with twin sides and twin angles at the "base", let's check what the angle at R is, 15(7) - 31 = 74, and her twin sister at T is also 74, that means that the angle at S is 180 - 74 - 74 = 32.

4 0

2 years ago

What scale factor was used to dilate figure a to get figure b ?

Ghella [55]

A scale factor of 3 was used, because Figure B's measurements are 3 times Figure A's measurements.
Hope that helped!

5 0

3 years ago

Read 2 more answers

Consider the line y = 7x-9.

KatRina [158]

$y = \frac{-1}{7}x -\frac{8}{7}$ is the equation of the line that is perpendicular to this line and passes through the point (6, -2)

y = 7x - 44 equation of the line that is parallel to this line and passes through the point (6, -2)

Solution:

Given that line is:

y = 7x - 9

The equation of line in slope intercept form is given as:

y = mx + b ------ eqn 1

Where, "m" is the slope of line and "b" is the y intercept

On comparing eqn 1 with y = 7x - 9 we get,

m = 7

<h3>Find the equation of the line that is perpendicular to this line and passes through the point (6, -2)</h3>

We know that,

Product of slope of a line and slope of line perpendicular to given is always -1

Therefore,

$7 \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{-1}{7}$

Now find the equation of line:

$\text{ Substitute } m = \frac{-1}{7} \text{ and } (x, y) = (6, -2) \text{ in eqn 1}$

$-2 = \frac{-1}{7} \times 6 + b\\\\-2 = \frac{-6}{7} + b\\\\b = -2+\frac{6}{7}\\\\b = \frac{-14+6}{7}\\\\b = \frac{-8}{7}$

$\text{Substitute } m = \frac{-1}{7} \text{ and } b = \frac{-8}{7} \text{ in eqn 1}\\\\y = \frac{-1}{7}x -\frac{8}{7}$

Thus the equation of line perpendicular to given line is found

<h3>Find the equation of the line that is parallel to this line and passes through the point (6, -2)</h3>

Slopes of parallel lines are equal

Therefore, m = 7

Substitute m = 7 and (x, y) = (6, -2) in eqn 1

-2 = 7(6) + b

-2 = 42 + b

b = -44

Substitute m = 7 and b = -44 in eqn 1

y = 7x - 44

Thus equation of line parallel to given line is found

8 0

2 years ago

1).Calculate T, when sample mean is 120, population mean is 100, standard deviation is 20 and smaple size is 10 using levels of

Sonbull [250]

Answer:

$t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16$

$p_v =2*P(t_{9}>3.16)=0.012$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=120$ represent the sample mean

$s=20$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =100$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 100, the system of hypothesis would be:

Null hypothesis: $\mu = 100$

Alternative hypothesis: $\mu \neq 100$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=10-1=9$

Conclusion

Since is a tao tailed test the p value would be:

$p_v =2*P(t_{9}>3.16)=0.012$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.

8 0

3 years ago

Read 2 more answers

Hey need some help quick

Goryan [66]

If $z=\pm 15i$ has to be a solution of the equation, just plug it in: