From the equation of motion, we know,
Where s= displacement
u= initial velocity
a= gravitational force
t= time
Displacement is 0 since the ball comes back to the same point from where it was thrown.
A = 
since the ball is thrown upwards.
Plug the known values into the equation.
=> 
Solving for u gives :
u= 16.67 m/ sec ....... equation (1)
At maximum height, final velocity i.e v is 0
Time take to reach the top = 
=> 
Solving for s we get
s= 14.16 m
For this case, the first thing we must do is identify the linear expressions.
first linear expression = y1 = x
second linear expression = y2 = 5
We have then that the difference of the second with respect to the first is:
y2-y1 = 5-x
Answer:
The difference when the second line is here is subtracted from the first is:
5-x
The line y = 8x passes through the origin, which is the point (0, 0).
We say the ordered pair (0, 0) lies on the graph y = 8x.
Answer:
Step-by-step explanation:
First you need to do 5x5=25
