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hoa [83]
2 years ago
5

PLS SOMONE PLS FILL OUT I WILL GIVE BRAINLIEST HURRYYY

Chemistry
1 answer:
Soloha48 [4]2 years ago
8 0

Answer:

ano yarnnn????? dko maintindihan

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How many oxygen atoms are contained in the following chemical formula? 2agno3
sesenic [268]

It would be: 2*3 = 6 oxygen atoms

OPTION D IS YOUR ANSWER......

7 0
3 years ago
A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som
Andrews [41]

The given question is incomplete. The complete question is as follows.

A certain liquid has a normal boiling point of 124.2^{o}C and a boiling point elevation constant k_{b} = 0.62 ^{o}C kg mol^{-1}. A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at 127.4^{o}C. Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.

Explanation:

As per the colligative property, the elevation in boiling point will be as follows.

     

T = boiling point of the solution =

T_{o} = boiling point of the pure solvent = 124.2^{o}C

K_{b} = elevation of boiling constant = 0.62 ^{o}C kg mol^{-1}

We will calculate the molality as follows.

     molality = \frac{\text{maas of solute}}{\text{molar mass of solute}} \times \frac{1000}{\text{mass of solvent in g}}

i = vant hoff's factor

As NaCl is soluble in water and dissociates into sodium and chlorine ions so i = 2.

Putting the given values into the above formula as follows.  

    T - T_{o} = i \times K_{b} \times \text{molality of solution}

  (127.4 - 124.2)^{o}C = 2 \times 0.62 \times \frac{m}{60} \times \frac{1000}{650}

                  m = 100 g

Therefore, we can conclude that 100 g of NaCl was dissolved.

3 0
3 years ago
Assuming 100% dissociation, calculate the freezing point and boiling point of 1.22 m SnCl₄(aq). Constants may be found here.
Gekata [30.6K]

Answer:

T° freezing solution → -11.3°C

T° boiling solution → 103.1 °C

Explanation:

Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"

This salt dissociates as this:

SnCl₄ (aq)  →   1Sn⁴⁺ (aq)  +   4Cl⁻  (aq)   (so i =5)

The formula for the colligative property of freezing point depression and boiling point elevation are:

ΔT = Kf . m . i

where ΔT = T° freezing pure solvent - T° freezing solution

ΔT = Kb . m . i

where ΔT = T° boiling solution - T° boiling pure solvent

Freezing point depression:

0° - T° freezing solution = 1.86°C/m . 1.22 m . 5

T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C

Boiling point elevation:

T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5

T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C

8 0
3 years ago
To dissolve in water, aluminum (AI) should form a compound with
astra-53 [7]

Answer:

Explanation:

Nitrate of most of the elements are water soluble . Aluminium nitrate is also one of them . Aluminium nitrate is easily dissolved in water . It forms hydrated salt whose formula is as follows

Al( NO₃ )₃ . 9H₂O

It is a white crystalline salt . It is also soluble in alcohol.

7 0
3 years ago
What causes a zip line rider move?
jeyben [28]
The steeper it is the more it moves
4 0
2 years ago
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