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2 years ago

What type of change is this picture showing?

Chemistry

1 answer:

sladkih [1.3K]2 years ago

8 0

Answer: physical

Explanation: freezing and melting are physical changes.

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The enthalpy of formation of MX is ΔHf° = –525 kJ/mol. The enthalpy of sublimation of M is ΔHsub = 139 kJ/mol. The ionization en

polet [3.4K]

I'm sorry but could you tell me IE2 I couldn't asks for details

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2 years ago

What is included in a compaarative investigation

Minchanka [31]

a scientific question

6 0

3 years ago

A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

2 years ago

How to check atomic mass?

slavikrds [6]

Answer:

There are multiple ways to check mass but I'll tell you one. Look below

Explanation:

One easy way of checking atomic mass is by adding protons and neutrons.

For example:

We have 5 protons and 4 neutrons.

5+4=9

I hope this helps (:

8 0

3 years ago

Find the value of x in the triangle

myrzilka [38]

Answer:

55.52°

Explanation:

Concept tested: Sine rule of triangles

We need to know the sine rule

According to sine rule, if the three sides of a triangle are a, b and c and the corresponding angles, A, B and C

Then, $\frac{a}{SinA}=\frac{b}{SinB}=\frac{c}{SinC}$

In this case;

If we take, a = 5.7 units and A = 70°, and

b= 5 units, B = x°

Using the sine rule we can find the value of x

Therefore;

$\frac{a}{SinA}=\frac{b}{SinB}$

Then;

$\frac{5.7}{Sin70}=\frac{5}{Sinx}$

$6.0658=\frac{5}{sinx}$

$Sinx=0.8243$

Therefore, X = 55.52°

Therefore, the value of x in the triangle is 55.52°

6 0

2 years ago