Answer:
stem is the correct answer
Explanation:
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Answer:
1x10^-3M
Explanation:
Data obtained from the question include:
pH = 3
[H3O+] =?
The concentration of the hydronium ion [H3O+] can be obtained by using the formula pH = - Log [H3O+] as illustrated below:
pH = - Log [H3O+]
3 = - Log [H3O+]
Divide through by - 1
- 3 = Log [H3O+]
Take the anti-log of - 3
[H3O+] = 1x10^-3M
Therefore, the concentration of the hydronium ion [H3O+] is 1x10^-3M
ΔG > 0
is always true for the freezing of water.
Explanation:
- The freezing of water is only spontaneous when the temperature is fairly small. Over 273 K, the higher value of TΔS causes the sign of ΔG to be positive, and there is no freezing point.
- The entropy decreases as water freezes. This does not infringe the Thermodynamics second law. The second law doesn't suggest entropy will never diminish anywhere.
- Entropy will decline elsewhere, provided it increases by at least as much elsewhere.
1) Calculate the number of moles of Cu SO4 . 5H20 by dividing the specified mass by the molar mass.
2) The ratio of production given by the equation is 1 mol of Cu SO4 . 5 H2O to 1 mol of Cu SO4=> 1:1, meaning that the number of moles of Cu SO4 produced is the same number of moles of Cu SO4.5H20 heated.
3) Finally mutiply the number of moles of Cu SO4 by its molar mass and there you have the mass of Cu SO4 produced.